<span>Don't forget S is measured in thousands of units so you are solving for :
100 < 74.5 + 43.75Sin(πt/6)
25.5 < 43.75Sin(πt/6)
Sin(πt/6) >25.5/43.75 = 0.582857
ASrcSin(πt/6) > 0.62224 radians
πt/6 > 0.62224
t > 6 x 0.62224/π = 1.1884 (4dp)
This initial value occurs when the sine value is increasing and it will reach its maximum value of 1 when Sin(πt/6) = Sinπ/2, that is when t = 3.
Consequently, monthly sales exceed 100,000 during the period between t = 1.1884 and 4.8116
[3 - 1.1884 = 1.8116 so the other extreme occurs at 3 + 1.8116]
Note : on the basis of these calculations, January is 0 ≤ t < 1 : February is 1 ≤ t < 2 :....May is 4 ≤ t < 5
So the period when sales exceed 100,000 occurs between Feb 6 and May 25 and annually thereafter.</span>
Answer:
C) 1/6^32
Step-by-step explanation:
The applicable rules of exponents are ...
(a^b)^c = a^(b·c)
(a^b)(a^c) = a^(b+c)
a^-b = 1/a^b
_____
Using these rules, your expression simplifies to ...
6^8·6^(10(-4)) = 6^8·6^-40 = 6^(8-40) = 6^-32 = 1/6^32
Answer:
d
Step-by-step explanation:
Answer: -1410
Step-by-step explanation:
Let's start by subbing in -4 for x

Now we can solve
