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viva [34]
2 years ago
15

Which should you use to find a saved file?

Computers and Technology
2 answers:
Arlecino [84]2 years ago
8 0

Answer:

C. search box

Explanation:

however that functionality doesnt work as well since the advent of windows xp

stellarik [79]2 years ago
7 0

Answer:

The correct answer is letter "C": Search Box.

Explanation:

The "Search Box" is a tool that allows looking for different types of files stored in the hard drive. For this matter, it is necessary to know under what name the file was saved otherwise it will be impossible to find it. Misspellings could make this task difficult but, fortunately, the tool is not case sensitive so it does not matter if the file name is in upper or lower case.

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Explanation:

if it got water in it that should help it.

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Identify a statement that accurately differentiates between short-term memory and working memory.
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Look at the logic program below. Set a breakpoint after each commented instruction. You can also single step through the program
Goshia [24]

Using programming knowledge, it is possible to use programming logic, we can differentiate and find the terms

<h3>Writing the code and understanding the programming logic:</h3>

<em>.data</em>

<em>sourceword:</em>

<em>.word 0xAB</em>

<em>wordmask:</em>

<em>.word 0xCF</em>

<em>operand:</em>

<em>.long 0xAA</em>

<em>.text</em>

<em>.globl _start</em>

<em>_start:</em>

<em>movw sourceword, %ax # ax=0x00AB ( move the word value of sourceword =0x00AB to ax register.)</em>

<em>movw %ax, %bx # bx=0x00AB ( copy the value of ax to bx register.)</em>

<em>xorw %cx, %cx # cx=0000 ( cx=cx XOR cx, that is clear cx register.)</em>

<em />

<em>andw wordmask, %ax # ax=0x008B ( ax=ax AND wordmask= 0x00AB AND 0x00CF= 0x008B)</em>

<em>orw wordmask, %bx # bx=0x00EF (bx=bx OR wordmask= 0x00AB OR 0x00CF= 0x00EF.)</em>

<em>xorw wordmask, %cx # cx=0x00CF (cx=cx XOR wordmask= 0x0000 XOR 0x00CF=0x00CF.)</em>

<em />

<em>movl operand, %eax # eax=0x000000AA. ( copy the 32-bit value of operand=0x000000AA to eax.)</em>

<em>movl %eax, %ebx # ebx=0x000000AA.( copy the value of eax to ebx.)</em>

<em>movl %eax, %ecx # ecx=0x000000AA. ( copy the value of eax to ecx.)</em>

<em />

<em>shll $3,%eax # eax=0x00000550. ( logical shift left of eax=0x000000AA by 3 bits.)</em>

<em />

<em># 0x000000AA=00000000000000000000000010101010</em>

<em />

<em># =>00000000000000000000010101010000=0x00000550.</em>

<em />

<em>rorl $4,%ebx # ebx=0xA000000A. (Rotate right ebx=0x000000AA by 4 bits.)</em>

<em />

<em># 0x000000AA=00000000000000000000000010101010</em>

<em />

<em>3 =>10100000000000000000000000001010= 0xA000000A.</em>

<em />

<em>sarl %ecx # here the count value to shift the bits not mentioned.</em>

<em />

<em># It is the arithmetic shift right instruction. the shifted left bits filled with MSB bit.</em>

See more about logic program at brainly.com/question/14970713

#SPJ1

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zysi [14]

Answer:

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Explanation:

its copy and paste

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3 years ago
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