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BaLLatris [955]
3 years ago
13

Compared with other PC operating systems, the Linux-based operating systems:

Computers and Technology
1 answer:
eduard3 years ago
7 0

The PC operating systems are operating systems that run on personal computers

<em>The Linux-based operating system are (a) free or very inexpensive</em>

Several operating systems run on PC; the most popular are <em>Windows, Linux and, macOS</em>.

  • The Windows operating system costs between $100 and $250, for a genuine copy
  • The macOs costs between $69 and $115, for a genuine copy

However, the Linux operating system is free, and it is also open source.

Hence, in comparison to the other PC operating systems, the Linux based operating system is <em>free or very inexpensive</em>

Read more about operating systems at:

brainly.com/question/2126669

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Tricking someone else into sharing private information, then posting it publicly online, is a form of which type of cyberbullyin
Alisiya [41]
If the bully did not first befriend the person, it’s outing. If he did, then it’s trickery.
5 0
3 years ago
What is 8 hours, 5 minutes, 22 seconds minus (-) 7 hours, 24 minutes, 37 seconds?
olga_2 [115]

Answer:

Enter time 1 HH:MM:SS8:5:22                                                                                                    

Enter time 2 HH:MM:SS7:24:37                                                                                                  

0:40:45

Explanation:

The program for above in Python is:

from datetime import datetime

s1 = input("Enter time 1 HH:MM:SS")

s2 = input("Enter time 2 HH:MM:SS")

Format1 = '%H:%M:%S'

tdiff = datetime.strptime(s1, Format1) - datetime.strptime(s2, Format1)

print(tdiff)

We are using the datetime class in datetime module for using strptime to find the difference between the two times.

3 0
4 years ago
Input 3 positive integers from the terminal, determine if tlrey are valid sides of a triangle. If the sides do form a valid tria
butalik [34]

Answer:

In Python:

side1 = float(input("Side 1: "))

side2 = float(input("Side 2: "))

side3 = float(input("Side 3: "))

if side1>0 and side2>0 and side3>0:

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

       if side1 == side2 == side3:

           print("Equilateral Triangle")

       elif side1 == side2 or side1 == side3 or side2 == side3:

           print("Isosceles Triangle")

       else:

           print("Scalene Triangle")

   else:

       print("Invalid Triangle")

else:

   print("Invalid Triangle")

Explanation:

The next three lines get the input of the sides of the triangle

<em>side1 = float(input("Side 1: ")) </em>

<em>side2 = float(input("Side 2: ")) </em>

<em>side3 = float(input("Side 3: ")) </em>

If all sides are positive

if side1>0 and side2>0 and side3>0:

Check if the sides are valid using the following condition

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

Check if the triangle is equilateral

<em>        if side1 == side2 == side3: </em>

<em>            print("Equilateral Triangle") </em>

Check if the triangle is isosceles

<em>        elif side1 == side2 or side1 == side3 or side2 == side3: </em>

<em>            print("Isosceles Triangle") </em>

Otherwise, it is scalene

<em>        else: </em>

<em>            print("Scalene Triangle") </em>

Print invalid, if the sides do not make a valid triangle

<em>    else: </em>

<em>        print("Invalid Triangle") </em>

Print invalid, if the any of the sides are negative

<em>else: </em>

<em>    print("Invalid Triangle")</em>

4 0
3 years ago
Professor Gekko has always dreamed of inline skating across North Dakota. He plans to cross the state on highway U.S. 2, which r
geniusboy [140]

The efficient algorithm by which he can determine which water stops he should make; <em>has been determined below and the strategy which is the greedy strategy has been proven to yield an optimal solution.</em>

<em />

To solve this question optimally, we will make use of the greedy solution.

In this method, we will maximize the distance that can be covered from a particular point in such a way that there must be a place where water can be gotten before a run out is experienced.

Now, the first point at which there will be a stop should be located at a point that is farthest from the starting position and is also made to be ≤ m miles from the starting position.

Now, this this situation is one that shows optimal substructure and since our  first stopping point will be made to be at p, it means that we are solving the sub-question with the assumption that our starting point is at p.

When we combine the two stated plans above, we will arrive at an optimal solution for the normal reasons via cut and paste.

B) Now we need to show that the greedy approach earlier used produce a first stopping point which is contained in the optimal solution.

Let O represent any optimal solution whereby the professor stops at positions o₁, o₂, o₃....oₙ.

Let h₁ represent the farthest stopping point that is reachable from the starting point. Then we can replace o₁ by h₂ to generate a modified solution H since o₁ - o₂ < o₂ - h₁.

Finally, we can really make it to the positions in H without having to run out of water and since H has the same number of stops, we can conclude that h₁   is contained in one of optimal solution.

Therefore our strategy which is the greedy strategy has been proven to work.

Read more about algorithms at; brainly.com/question/24793921

8 0
2 years ago
Which steps allow a user to change the column layout in the Handout Master?
sukhopar [10]

Answer:

It's D

Explanation:

On edgenuity

7 0
4 years ago
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