Vcylinder-Vsphere=water
Vcylinder=hpir^2
Vsphere=(4/3)pir^3
given
cylinderradius=30 and h=100
Vcylinder=100pi30^2=100pi900=90000pi
let's leave it in terms of pi for more exactness
sphereradius=12
Vsphere=(4/3)pi12^3=2304pi
cylinder-sphere=90000pi-2304pi=87696pi
using pi=3.14
water=275365.44 cubic cm
last option is corrrect
Answer:
106
Explanation:
3a+b2
Substitute the values for the variables:
3(14) + 2(32)
Solve:
3(14) + 2(32)
42 + 64
106
a. Answer: m = 2
<u>Step-by-step explanation:</u>
f(x) = x² - 4x + 1
f(m) = m² - 4m + 1 = -3
m² - 4m + 4 = 0
(m - 2)(m - 2) = 0
m = 2
***************************************************
b. Answer: k = 2 and k = 5
<u>Step-by-step explanation:</u>
f(x) = x² - 7x + 14
f(k) = k² - 7k + 14 = 4
k² - 7k + 10 = 0
(k - 2)(k - 5) = 0
k = 2 k = 5
Answer:
option 4. The graph has zeroes at x = 15 an x = -15 and it opens upward.
Step-by-step explanation:
we have
This is the equation of a vertical parabola open upward (the leading coefficient is positive)
The vertex represent a minimum
The vertex is the point (0,-225)
The axis of symmetry is x=0 (y-axis)
Find the x-intercepts (values of x when the value of y is equal to zero)
For y=0
square root both sides
therefore
The graph has zeroes at x = 15 an x = -15 and it opens upward.
Answer:
14.4 to nearest tenth.
Step-by-step explanation:
By the Pythagoras theorem:-
Distance = √ [ (y2-y1)^2 + (x2-x1)^2 ] where the 2 points are (x1,y1) and (x2,y2)
= √ [ (16-4)^2 + (9-1)^2]
= √ 208
= 14.4
