Answer:
The amount she started with $20
Step-by-step explanation:
Let the amount Ahmya started with = x
when she bought $10 shirt, the remaining money is = x - 10
she spent half of this remaining money on dinner = 
amount left after this =
she further spent $4 on cofee, the remaining money = - 4
she also spent 1/4 of remaining money on souveniers = 
amount left = 
The two last fractions should sum up to 1;
x = $20
Therefore, the amount she started with $20
Answer:
1/5
Step-by-step explanation:
Your equation is written in the form y=mx+b, where m is the slope and b is the y-intercept.
m=1/5, so the slope is 1/5
Answer:
We are given the t distribution with 16 degrees of freedom.
We have to find the area a. to the right of 2.120
Answer: We can use excel to find the area to the right of 2.120. The excel function is:
=TDIST(2.120,16,1) = 0.025
Therefore, the area to the right of 2.120 is 0.025
b. to the left of 1.337.
Answer: We can use excel to find the area to the left of 1.337. The excel function is:
=1 - TDIST(1.337,16,1) = 0.900
Therefore, the area to the left of 1.337 is 0.900
❤️Hello!❤️For experimental data it may be good to use linear regression.
For precise data you do not need linear regression.
Step-by-step explanation: If you have a number of experimentally generated data points that are subject to inaccuracies then you can use something like linear regression to generate a linear model that fits the data reasonably well. Many modern calculators have a linear regression capability.
On the other hand, if you are given precise data, you should be able to generate a model that fits the data exactly. For example, given points (
x
1
,
y
1
) and (
x
2
,
y
2
) which are supposed to lie on a line, the equation of the line in point-slope form is:
y
−
y
1
=
m
(
x
−
x
1) where m
=
y
2
−
y
1
x
2
−
x
1 from which we can derive the slope-intercept form:
y
=
m
x
+
c where c
=
y
1
−
m
x
1. ☯️Hope this helps!☯️ ↪️ Autumn ↩️
Answer:
<em>hello your question lacks some information attached below is the complete question</em>
answer : NO
Step-by-step explanation:
Determine the probability of not selecting an obese subject in 3 trials
= P ( not obese in 3 randomly selected ) = ( 1 - 0.111 )^3
= 0.703
The probability > 0.05
hence it is insignificant therefore the answer is NO
