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Hitman42 [59]
3 years ago
13

Find the distance between the points (0, 2) and (4, 5).

Mathematics
1 answer:
miv72 [106K]3 years ago
8 0

Answer:

3/4

Step-by-step explanation:

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Is the first number a multiple of the second? 56, 8:
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Answer:

no

Step-by-step explanation:

no bc 8 is a multiple of 56, not 56 a multiple of 8

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Given the slope and ordered pair write in y=mx+b form<br> slope: 7/9, ordered pair: (0,−8/9)
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The answer to the question

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What is the slope of the line shown in the graph? (4 points)
Korvikt [17]

Answer:

a. or \frac{3}{-2}

Step-by-step explanation:

Slope is equal to y1-y2 over x1-x2.

So the equation would be:

\frac{2-(-1)}{-3-(-1)}

2-(-1)=2+1=3

-3-(-1)=-3+1=-2

So the answer is:

\frac{3}{-2}

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5(6x+5)-2(4x-1) = 30x+25-8x+2 = 22x+27
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3 years ago
A manufacturer has been selling 1000 flat-screen TVs a week at $500 each. A market survey indicates that for A manufacturer has
luda_lava [24]

Answer:

a) Demand function: q=6000-10\cdot p

b) The rebate should be of $200, so the sale price becomes $300 per unit.

c) The rebate should be of $150, so the sale price becomes $350 per unit.

Step-by-step explanation:

a) In this case, we have a known point of the demand function (1000 units sold at $500), and the slope of a linear function (increase by 100 units fora decrease in $10).

We can express the demand function (linear) as:

q=b+m\cdot p

To calculate the slope m, we use:

m=\Delta q/\Delta p=(+100)/(-10)=-10

To calculate b, we use the known point and the calculated slope:

q=b+m\cdot p\\\\b=q-m\cdot p=1000-(-10)\cdot (500)=1000+5000=6000

Then the demand function is:

q=6000-10\cdot p

b) The revenue can be expressed as:

R=q\cdot p = (6000-10p)\cdot p=6000p-10p^2

To maximize, we can derive and equal to zero

dR/dp=6000-2*10p=0\\\\20p=6000\\\\p=300

The rebate should be of $200, so the sale price becomes $300 per unit.

c) If we take into account the cost, we have that

R=q\cdot p-C=(6000p-10p^2)-(68000+100q)\\\\R=(6000p-10p^2)-(68000+100(6000-10p))\\\\R=6000p-10p^2-(68000+600000-1000p)\\\\R=-10p^2+7000p-668000

To maximize, we can derive and equal to zero

dR/dp=-20p+7000=0\\\\p=7000/20=350

The rebate should be of $150, so the sale price becomes $350 per unit.

5 0
3 years ago
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