A) 460 ≥9.50h+60
B) the minimum of hours Jessie can work is about 42 hours.
A) I would make the positive integer x and then form an equation.
x + 30 = x^2 - 12
x + 42 = x^2
0 = x^2 - x - 42 this can be factorised
(x - 7) ( x + 6) Therefore x = 7 or x = -6
Since the question asks for a positive integer the answer is 7.
B) two positive numbers x and y.
X - y = 3
x^2 + y^2 = 117
Use these simultaneous equations to figure out each number.
Rearrange the first equation
x = y + 3
Then substitute it into the second equation.
(y+3)^2 + y^2 = 117
y^2 + 6y + 9 + y^2 = 117
2y^2 + 6y - 108 = 0
then factorise this.
(2y - 12) (y + 9)
This means that y = 6 or y = -9 but it’s 6 because that’s the only positive number.
Use y to find x
x = y + 3
x = 6 + 3
x = 9
So the answers are x = 9 and y = 6.
<em>Directed numbers</em> are numbers that have either a <u>positive</u> or <u>negative </u>sign, which can be shown on a <em>number line</em>. Therefore, point F is Fifteen-halves of line <em>segment</em> DE.
A <u>number line</u> is a system that can show the positions of <em>positive</em> or <em>negative</em> numbers. It has its <em>ends</em> ranging from <em>negative infinity</em> to <em>positive infinity</em>. Thus any <em>directed</em> number can be located on the line.
Directed numbers are numbers with either a <u>negative</u> or <u>positive </u>sign, which shows their direction with respect to the <em>number line.</em>
In the given question, the <u>distance</u> between points D and E is <em>9 units</em>. So that <em>dividing</em> 9 units in the ratio of 5 to 6, we have;
x 9 = 
= 
Therefore, the <em>location</em> of point F, which <u>partitions</u> the directed line segment from d to E into a 5:6 ratio is
. Thus the<em> answer</em> is <u>Fifteen-halves.</u>
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The substitution that should be used to rewrite 6(x+5)^2 + 5(x+5) - 4 = 0 is u = x + 5
<h3>Quadratic equations</h3>
These are equations that has a leading degree of 2. Given the expression
6(x+5)^2 + 5(x+5) - 4 = 0
In order to simplify this equation, we will replace the reoccuring term by a variable.
From the equation we can see that (x+5) is occuring the most. Let u = x + 5 so that:
6u^2 - 5u - 4 = 0
Hence the substitution that should be used to rewrite 6(x+5)^2 + 5(x+5) - 4 = 0 is u = x + 5
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