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anastassius [24]
3 years ago
7

Which one of the following choices best represents a long-term benefit of Cardio respiratory fitness

Physics
1 answer:
miskamm [114]3 years ago
8 0
Where are the choices?
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A 700 kg racecar slowed from 30 m/s to 15 m/s. What was the change in momentum?
xxMikexx [17]
Momentum equation is

change in momentum = mass•initial velocity•final velocity

so....

p=700(15) because your initial is 30, and your final in 15, so you subtract! hope that helped!
8 0
3 years ago
What is the force on a 976kg vehicle that accelerates at 2.5m/s
mel-nik [20]

Answer:

2440 N

Explanation:

As,F=m*a.....

From the question we have

force = 976 × 2.5

We have the final answer as

2440 N

8 0
3 years ago
The threaded shaft of a bolt is 33 mm long and its pitch is
Nata [24]

Answer:

It would take 30 turns

Explanation:1.1 times 30=33

5 0
3 years ago
A tank whose bottom is a mirror is filled with water to a depth of 20.0 cm. A small fish floats motionless 7.0 cm under the surf
liberstina [14]

Answer:

The apparent depth of (a) the fish is 5.3 cm and (b) the image of the fish is 24.8 cm.

Explanation:

According to the following equation:

\frac{n_{w} }{s} +\frac{n_{a} }{s'} = \frac{n_{a}- n_{w}}{R_{c} } \\

where <em>nw</em> and <em>na</em> is the refractive indices of water (1.33) and air (1.00) respectively; <em>s</em> is the depth of the fish below the surface of the water; s' is the apparent depth of the fish from normal incidence and Rc is the radius of curvature of the mirror at the bottom of the tank.

Note that the bottom of the tank is assumed to be a flat mirror, therefore the radius of curvature is very large (R⇒∞).

Therefore, the above equation can be expressed as:

\frac{n_{w}}{s} +\frac{n_{a}}{s'}=0

Now we can solve for the apparent depth of the fish.

(a) s'=-(\frac{n_{a}}{n_{w}})x s (Make s' subject of the formula from the above equation)

s'=(\frac{1.00}{1.33} )x7cm

∴ s'=5.3 cm.

(b) The motionless fish floats 13 cm above the mirror, therefore the image of the fish will be situated at 13 + 20 =33 cm away from the real fish.

Therefore, s = 33 cm

s'=-(\frac{n_{a}}{n_{w}})x s

s'=(\frac{1.00}{1.33} )x 33 cm

s'=24.8 cm.

NB: Here, it is assumed that the water is pure, as impurities may alter the refractive index of water.

8 0
4 years ago
Find the mass of oxygen in the 10 liter cylinder if at temperature 286 Kelvin the pressure P=9000000Pa. HELP PLS IM DESPERATE
spin [16.1K]
Did you try converting your equation into Kelvin scale form?
3 0
4 years ago
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