In how many ways can 10 people wait in line for concert tickets

Mathematics

2 answers:

Mrrafil [7]3 years ago

8 0

10 * 1 *2 *3*4*5*6*7*8*9
3628800 is the answer

BabaBlast [244]3 years ago

4 0

Use a permutation. There are 20,274,200 combinations of ways to wait in line for ten people.

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Gnom [1K]

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<em><u>Solution:</u></em>

Let "d" be the number of dimes

Let "q" be the number of quarters

We know that,

value of 1 dime = $ 0.10

value of 1 quarter = $ 0.25

Given that LIzzie has 30 coins

number of dimes + number of quarters = 30

d + q = 30 ---- eqn 1

Also given that the coins total $ 4.80

number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 4.80

$d \times 0.10 + q \times 0.25 = 4.80$

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Let us solve eqn 1 and eqn 2

From eqn 1,

d = 30 - q ---- eqn 3

Substitute eqn 3 in eqn 2

0.1(30 - q) + 0.25q = 4.8

3 - 0.1q + 0.25q = 4.8

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From eqn 3,

d = 30 - 12

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