The function is an exponential with base greater than 1. So, its range is , with 0 being the horizontal asymptote as .
If you multiply the function by , the range remains the same.
If you reflect it over the x-axis, you're changing the sign of the function. So, the new range is
Answer:
c. Ninety-five percent of the time, the percentage of those questioned who have read the Declaration of Independence would likely be between 25 and 33 percent.
Step-by-step explanation:
Margin of error:
"It means the percentage difference of the result above or below the exact value."
i.e. 4 percent of margin error in the question means that the result will be either 4 percent above the 29 percent or 4 percent below the 29 percent.
OR "the result can vary upto 4 percent above or below the 29 percent."
Let me simplify the answer first in number then convert it percent to understand easily.
29 percent of 1000= (29/100)*1000=290
4 percent of 1000=(4/100)*1000=40
If 290 students had read the declaration of independence at least once with 40 margin of error, then it means the number of students that had read declaration of independence may be 330 or 250
250 is 25% of 1000 and 330 is 33% of 1000, that is why ninety-five percent of the time, the percentage of those questioned who have read the Declaration of Independence would likely be between 25 and 33 percent.
Answer:
a. H0 : p ≤ 0.11 Ha : p >0.11 ( one tailed test )
d. z= 1.3322
Step-by-step explanation:
We formulate our hypothesis as
a. H0 : p ≤ 0.11 Ha : p >0.11 ( one tailed test )
According to the given conditions
p`= 31/225= 0.1378
np`= 225 > 5
n q` = n (1-p`) = 225 ( 1- 31/225)= 193.995> 5
p = 0.4 x= 31 and n 225
c. Using the test statistic
z= p`- p / √pq/n
d. Putting the values
z= 0.1378- 0.11/ √0.11*0.89/225
z= 0.1378- 0.11/ √0.0979/225
z= 0.1378- 0.11/ 0.02085
z= 1.3322
at 5% significance level the z- value is ± 1.645 for one tailed test
The calculated value falls in the critical region so we reject our null hypothesis H0 : p ≤ 0.11 and accept Ha : p >0.11 and conclude that the data indicates that the 11% of the world's population is left-handed.
The rejection region is attached.
The P- value is calculated by finding the corresponding value of the probability of z from the z - table and subtracting it from 1.
which appears to be 0.95 and subtracting from 1 gives 0.04998
Since x=-10, plug that into the equation.
f(x) = 2(-10) + 11
= -20 + 11
y = -9
So the ordered pair in (x,y) terms is (-10,-9).
Answer:
The probability a person selected random is not suffering from Malaria is 0.725.
Step-by-step explanation:
Denote the events as follows:
X = a person is suffering from Malaria
M = a man
W = a woman
The information provided is:
P (M) = P (W) = 0.50
P (X|M) = 0.10
P (X|W) = 0.45
Compute the probability a person selected random is suffering from Malaria as follows:
Then the probability a person selected random is not suffering from Malaria is:
P (X') = 1 - P (X)
= 1 - 0.275
= 0.725