Let's actually find the line of best fit...
m=(nΣyx-ΣyΣx)/(nΣx^2-ΣxΣx)
m=(11*836-130*55)/(11*385-3025)
m=2046/1210
m=93/55
b=(Σy-93Σx/55)/n
b=(55Σy-93Σx)/(55n)
b=(7150-5115)/(55*11)
b=185/55, so the line of best fit is:
y=(93x+185)/55
A) The approximate y-intercept (the value of y when x=0) is 185/55≈3.36.
Which means that those who do not practice at all will win about 3.36 times
B) y(13)=(93x+185)/55
y(13)≈25.34
So after 13 months of practice one would expect to win about 25.34 times.
Answer:
<h2>It is Theoretical probability.</h2>
Step-by-step explanation:
Theoretical probability determines the likelihood of some incidents to happen.
Theoretical probability is the ratio between the total number of possible outcomes and the desired outcome.
Here, the desired outcome is getting a 2 that is only one desired outcome, where as total possible outcomes are 6. Here, the probability of getting a 2 is 
.
Empirical probability depends on observance. In the given question, nothing related to observance of the given incident has mentioned, hence it is not empirical probability.
N(N ∩ S ∩ K) = 10
n(ξ) = 250
n(S ∪ K) = 15 - 10 = 5
n(N ∪ S) = 20 - 10 = 10
n(N ∪ K) = 30 - 10 = 20
n(S) = 50 - 10 - 5 - 10 = 25
n(K) = 55 - 20 - 5 - 10 = 20
n(N) = 100 - 10 - 20 - 10 = 60
n(N ∪ S ∪ K) = 10 + 5 + 10 + 20 + 25 + 20 + 60 = 150
Therefore, n(N ∪ S ∪ K)' = 250 - 150 = 100
Therefore, 100 million people do not read any of the three papers.
If you mean it costs $1.49 to buy 10 items, then the unit rate is $0.15 or 15 cents
This is because you divide 1.49 over 10 like so: 1.49/10 = 0.149, then round this to the nearest penny to get 0.15
0.15 dollars = 15 cents
so basically whatever this item is, it costs 15 cents per item
