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scoundrel [369]
2 years ago
7

What is 2+2•67/19•34+1

Mathematics
2 answers:
snow_lady [41]2 years ago
7 0

2+2*67/19*34+1

2+\frac{134}{19}(34)+1

2+\frac{4556}{19}+1

\frac{4594}{19}+1

=\frac{4613}{19}

Hope this helps!

Thanks!

-Charlie

victus00 [196]2 years ago
5 0

Answer:

<h2>4613/19</h2>

Step-by-step explanation:

2 + 2 * 67/19 * 34 + 1\\2 + 134/19(34) +1\\2 + 4556/19 + 1\\4594/19 + 1\\ 4613/1

<em>I hope this helps :)</em>

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The length of one side of a triangular lot is 6 m less than 3 times the length of the second side. The third side is 8 m longer
Tanya [424]

second side = x

first side = 3x - 6

third side = (3x - 6) + 8

The perimeter = 80m and is equal x + (3x - 6) + [(3x - 6) + 8]

x + 3x - 6 + 3x - 6 + 8 = 80

7x - 4 = 80 |+4

7x = 84 |:7

x = 12 m

3x - 6 = 3(12) - 6 = 30 m

(3x - 6) + 8 = 3x + 2 = 3(12) + 2 = 38 m

Answer: 12m, 30m, 38m

8 0
3 years ago
A container holds 50 electronic components, of which 10 are defective.
Gala2k [10]

Answer:

There is some inforrmation that is missing in this question. It should read:

A container holds 50 electronic components, of which 10 are defective. If 6 components are drawn at random from the container, the probability that at least 4 are not defective is . If 8 components are drawn at random from the container, the probability that exactly 3 of them are defective is .

Answers

Part 1.   0.02

Part 2.  0.0375

Explanation

The probability is a chance of an event happening. It is calculated as;

probability = (Number of favourable outcome)/(Number of available outcome)

Part 1

6 are chosen at random. If 4 are not defective, then 2 are defective.

P(at least 4 are not defective) = 4/40 × 2/10

                                               = 1/10 ×1/5

                                               = 1/50

                                                = 0.02

Part 2

8 are chosen at random. If 3 are defective, the 5 are not defective.  

P(3 are defective) = 3/40 × 5/10  

                            = 15/400

                            = 3/80

                           = 0.0375

Step-by-step explanation:

4 0
3 years ago
I am doing homework can I please get some help?
Arada [10]

Answer:

i need point

Step-by-step explanation:

popopopo

5 0
3 years ago
Find a degree 3 polynomial with real coefficients having zeros 2 and 2 − 2 i and a lead coefficient of 1. Write P in expanded fo
Zanzabum

Answer:

The polynomial with real coefficients having zeros 2 and 2 - 2i is

x³ - 6x² + 16x - 16 = 0

Step-by-step explanation:

Given that a polynomial has zeros at 2 and 2 - 2i, we want to write this polynomial.

We have

x - 2 = 0

x - (2 - 2i) = 0

=> x - 2 + 2i = 0

Since the polynomial has real coefficients, and 2 - 2i is a zero of the polynomial, the conjugate of 2 - 2i, which is 2 + 2i is also a polynomial.

x - (2 + 2i) = 0

=> x - 2 - 2i = 0

Now,

P(x) = (x - 2)(x - 2 + 2i)(x - 2 - 2i) = 0

= (x - 2)((x - 2)² - (2i)²) = 0

= (x - 2)(x² - 4x + 8) = 0

= x³ - 4x² + 8x - 2x² + 8x - 16 = 0

= x³ - 6x² + 16x - 16 = 0

This is the polynomial required.

6 0
3 years ago
PLZ HELP ME<br> What value of x makes this equation true?<br><br> x/2−6=10
TiliK225 [7]

Answer:

a

Step-by-step explanation:

a

3 0
3 years ago
Read 2 more answers
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