Answer:
y=3×-11
Step-by-step explanation:
y=m+c
m=7-1÷6-4
m=6÷2
m=3
y=3+c
7=3(6)+c
7-18=c
-11=c
y=3×-11
Answer: 
Step-by-step explanation:
We know that the standard quadratic equation is ax^2+bx+c=0
Let's compare all the given equation to it and , find discriminant.
1. a=2, b= -7, c=-9
So it has 2 real number solutions.
2. a=1, b=-4, c=4
So it has only 1 real number solution.
3. a=4, b=-3, c=-1
So it has 2 real number solutions.
4. a=1, b=-2, c=-8
So it has 2 real number solutions.
5. a=3, b=5, c=3
Thus it does not has real solutions.
You are going in the right direction. For the distance of ST I get √136
√(-5-1)² + (6+4)² =
√(-6)² + (10²) =
√ 36 + 100 =
√136
√34² + √136² =√170²
34 + 136 = 170
170 = 170
We can either convert them to decimals or to fractions
if decimals
2/3=0.66666666
4/5=8/10=0.8
so the order is
-0.6, 0.65, 0.66, 0.8 or
-0.6, 0.65, 2/3, 4/5
if conver to fractions then
since -0.6 is negative, it is smallest, no need to convert
0.65=65 hundreths=65/100
2/3=66/99=prety close
4/5=8/10=80/100
order is
-0.6, 65/100, 66/99, 80/100 or
-0.6, 0.65, 2/3, 0.8
He would need a 93% on his fourth exam.
94+89+96+93= 372, 372 divided by 4= 93
