Question

Given that the commuter used public transportation, find the probability that the commuter had a commute of 60 6060 or more minutes. P ( 60 + minutes ∣ public transportation ) = P(60+ minutes ∣ public transportation)=P, left parenthesis, 60, plus, start text, space, m, i, n, u, t, e, s, space, end text, vertical bar, start text, space, p, u, b, l, i, c, space, t, r, a, n, s, p, o, r, t, a, t, i, o, n, end text, right parenthesis, equals

Answer 1

Complete Question

The two-way table below gives the thousands of commuters in Massachusetts in 2015 by transportation method and one-way length of commute.  

$\left|\begin{array}{c|c|c|c|c|c|c} Transport Mode/Minutes& Less than 15&15-29&30-44& 45-59& 60 or more & Total\\---&---&---&---&---&---&---\\ Private vehicle & 636&908&590&257&256&2647\\ Public Transportation&9&54&96&62&108&329 \\ Other&115&70&23&7&7&222\\---&---&---&---&---&---&---\\ Total&760&1032&709&326&371 &3198 \end{array}\right|$

Answer:

$\dfrac{108}{329}$

Step-by-step explanation:

From the table above

Total Number of commuters who used public transportation=329

Number of commuters who spent 60 or more minutes on public transportation=108

Therefore:

Given that a commuter used public transportation,  the probability that the commuter had a commute of 60 or more minutes:

P ( 60 + minutes ∣ public transportation ) = $\dfrac{108}{329}$