Answer:
The probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Step-by-step explanation:
Let the random variable <em>X</em> denote the water depths.
As the variable water depths is continuous variable, the random variable <em>X</em> follows a continuous Uniform distribution with parameters <em>a</em> = 2.00 m and <em>b</em> = 7.00 m.
The probability density function of <em>X</em> is:
Compute the probability that a randomly selected depth is between 2.25 m and 5.00 m as follows:
![=\frac{1}{5.00}\int\limits^{5.00}_{2.25} {1} \, dx\\\\=0.20\times [x]^{5.00}_{2.25} \\\\=0.20\times (5.00-2.25)\\\\=0.55](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B5.00%7D%5Cint%5Climits%5E%7B5.00%7D_%7B2.25%7D%20%7B1%7D%20%5C%2C%20dx%5C%5C%5C%5C%3D0.20%5Ctimes%20%5Bx%5D%5E%7B5.00%7D_%7B2.25%7D%20%5C%5C%5C%5C%3D0.20%5Ctimes%20%285.00-2.25%29%5C%5C%5C%5C%3D0.55)
Thus, the probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Answer:
Step-by-step explanation:
The pattern is going up by elevens each time. So basically you take the second number(A2) and subtract it from the first number(A1).
so short answer is: 46, 57, 68
Answer:
x=60.9°
Step-by-step explanation:
Given that the height of ball from the ground is 150ft
The base of the pole with the ball is 80 ft from where Trey is standing
Trey's horizontal line of sight is 6 feet above ground, then;
The height of ball from Trey's horizontal line of sight is;
150ft-6ft = 144ft
To find the angle x, assume a triangle with a base of 80 ft , a height of 144 ft and a slant height that represent the line of sight at an angle x
To get angle x , you apply the tangent of an angle formula where;
tan Ф°= length of opposite site of the angle/length of the adjacent side of the angle
tan x°= 144/80
tan x°= 1.8
x°= tan⁻(1.8)
x°=60.9°
Steven needs a total of 320 points to have a mean score of 80
Steven has 245 points so far
Steven needs to score at least 75 points on his last test to qualify for the team
