Answer:
6 and 8
Step-by-step explanation:
Let's start off by thinking at what the question is asking us.
The product (multiplication) of two even numbers (x)(x+2) is which means =,
12 more (12) than the square of the smaller number (x).
So put that all together and you get (x)(x+2)=12+x^2=
Distribute the x, (x)(x+2)=
x^2+2x=x^2+12 Subtract x^2 from both sides.
2x=12
Divide both sides by 2 and you get x=6
So the two numbers are 6,8
6(8)=12+6^2
48=48
Answer:
c > -7/8
Step-by-step explanation:
Add 2 for an inequality that compares to zero:
2x^2 -3x +(c+2) > 0
This will be true when the discriminant is negative. For the quadratic ...
ax^2 +bx +c
the discriminant is ...
b^ -4ac
We want this to be negative:
(-3)^2 -4(2)(c+2) < 0
9 -8(c +2) < 0
9 -8c -16 < 0
-7 < 8c
-7/8 < c
The given inequality will be true for all values of c greater than -7/8.
Answer:
7<em>x</em> + 10
Step-by-step explanation:
10 + 8<em>x</em> - 1<em>x</em>
<em>Add or subtract like terms.</em>
10 + (8 - 1)<em>x</em>
10 + (7)<em>x</em>
<em>Rearrange.</em>
7<em>x</em> + 10
Answer:3
Step-by-step explanation:
