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2 years ago

Help needed asap pleas3

Mathematics

1 answer:

Elis [28]2 years ago

5 0

17 is the answer your welcome

You might be interested in

8 numbers have a sum of 90. Whats the average number?

ehidna [41]

Answer:

$\huge\boxed{11.25}$

Step-by-step explanation:

When finding the average of a set of numbers, we

A) Add up all the numbers
B) Divide that sum by the total number of numbers in the data set

Let's represent this with a formula, s being the sum of all numbers, n being the total number of numbers.

$\frac{s}{n}$

Since we already know the sum and we know how many numbers there are (8), we can substitute inside our expression $\frac{s}{n}$ to find the average.

$\frac{90}{8}$
$11.25$

Therefore, the average of all these numbers is 11.25.

Hope this helped!

4 0

3 years ago

Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.

Sindrei [870]

Answer:

a) $P(X=3) = 0.1$

b) $P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

c) $P(X=4) = 0.3$

d) $P(X=0) = 0.2$

e) $E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

f) $E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

Step-by-step explanation:

We have the following distribution

x 0 1 2 3 4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

$P(X=3) = 0.1$

Part b

We want this probability:

$P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

Part c

For this case we want this probability:

$P(X=4) = 0.3$

Part d

$P(X=0) = 0.2$

Part e

We can find the mean with this formula:

$E(X)= \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

Part f

We can find the second moment with this formula

$E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

4 0

3 years ago

Please Help Meeee! Its a multiple answers..

Lelechka [254]

Answer:

B C E

Step-by-step explanation:

trust me... its too hard to explain

3 0

3 years ago

What is the domain of this table X 1 2 3 4 Y 2 4 3 2

Hoochie [10]

1,2,3,4 are the domain. The x column is always the domain.

3 0

3 years ago

What does the associative property state

TEA [102]

Answer:

The Associative property states that no matter which terms you combine first, the answer would be the same.

For example:

5 + (6 + 7) = (5 + 6) + 7

~Senpai

6 0

3 years ago

Help needed asap pleas3​

Help needed asap pleas3