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Taya2010 [7]
2 years ago
10

Help needed asap pleas3​

Mathematics
1 answer:
Elis [28]2 years ago
5 0
17 is the answer your welcome
You might be interested in
8 numbers have a sum of 90. Whats the average number?
ehidna [41]

Answer:

\huge\boxed{11.25}

Step-by-step explanation:

When finding the average of a set of numbers, we

  • A) Add up all the numbers
  • B) Divide that sum by the total number of numbers in the data set

Let's represent this with a formula, s being the sum of all numbers, n being the total number of numbers.

\frac{s}{n}

Since we <u>already know the sum</u> and we <u>know how many numbers there are</u> (8), we can substitute inside our expression \frac{s}{n} to find the average.

  • \frac{90}{8}
  • 11.25

Therefore, the average of all these numbers is 11.25.

Hope this helped!

4 0
3 years ago
Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.
Sindrei [870]

Answer:

a) P(X=3) = 0.1

b) P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

c) P(X=4) = 0.3

d) P(X=0) = 0.2

e) E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

f) E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

Step-by-step explanation:

We have the following distribution

x      0     1     2   3   4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

P(X=3) = 0.1

Part b

We want this probability:

P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

Part c

For this case we want this probability:

P(X=4) = 0.3

Part d

P(X=0) = 0.2

Part e

We can find the mean with this formula:

E(X)= \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

Part f

We can find the second moment with this formula

E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

4 0
3 years ago
Please Help Meeee! Its a multiple answers..​
Lelechka [254]

Answer:

B C E

Step-by-step explanation:

trust me... its too hard to explain

3 0
3 years ago
What is the domain of this table X 1 2 3 4 Y 2 4 3 2
Hoochie [10]
1,2,3,4 are the domain. The x column is always the domain.
3 0
3 years ago
What does the associative property state
TEA [102]

Answer:

The Associative property states that no matter which terms you combine first, the answer would be the same.

For example:

5 + (6 + 7) = (5 + 6) + 7

~<em>Senpai</em>


6 0
3 years ago
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