Find the limit, picture provided

Mathematics

1 answer:

Alex787 [66]3 years ago

5 0

Answer:

Step-by-step explanation:

You are given that

$\lim_{x \to 4} f(x)=5;$
$\lim_{x \to 4} g(x)=0;$
$\lim_{x \to 4} h(x)=-2.$

Use the rule

$\lim_{x\to x_0}(f(x)+g(x))=\lim_{x\to x_0} f(x)+\lim_{x \to x_0} g(x).$

In your case,

$\lim_{x\to4}(f+g)(x)=\lim_{x\to4} (f(x)+g(x))= \lim_{x\to4} f(x)+ \lim_{x\to 4} g(x)=5+0=5.$

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algol [13]

Answer:

A = 23.6 units^2

Step-by-step explanation:

Let the base be 8 (as shown).

Find the height of the triangle: Find the supplement of the 100 degree angle; it is (180 - 100), or 80 degrees. The side "opposite" this 80-degree angle is the height of the triangle:

height

sin 80 degrees = ---------------

and so the height of the triangle is h = 6 sin 80 degrees, or 5.91 units.

The area of the triangle is found using A = (1/2)(base)(height), which here amounts to:

A = (1/2)(8 units)(5.91 units), or

A = 23.64 units^2, or A = 23.6 units^2

3 0

4 years ago

What is the answer to K/2+1-1k=-2k

Mazyrski [523]

$\dfrac{k}{2}+1-1k=-2k\\\\\dfrac{1}{2}k+1-k=-2k\\\\\left(\dfrac{1}{2}k-k\right)+1=-2k\\\\-\dfrac{1}{2}k+1=-2k\qquad\text{subtract 1 from both sides}\\\\-\dfrac{1}{2}k=-2k-1\qquad\text{add 2k to both sides}\\\\1\dfrac{1}{2}k=-1\qquad\text{convert the mixed number to improper fraction}\\\\\dfrac{1\cdot2+1}{2}k=-1\\\\\dfrac{3}{2}k=-1\qqua\text{multiply both sides by}\ \dfrac{2}{3}\\\\\boxed{k=-\dfrac{2}{3}}$