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snow_tiger [21]
4 years ago
6

Answerrrrrrrrrrrrrrrrrrrrrr nowwwwwww

Mathematics
1 answer:
MrMuchimi4 years ago
7 0

\rm{\pink{\underline{\underline{\blue{ANSWER:-}}}}}

  • √64 = 8

  • \rm{8\dfrac{1}{7}\:=\:57/7} = 8.142

  • \rm{8.\overline{14}} = 8.1414..

  • 15/2 = 7.5

=> 8.142 > 8.1414 > 8 > 7.5 .

\rm\red{\therefore} 2) \rm{8\dfrac{1}{7}} , \rm{8.\overline{14}} , √64 , 15/2

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James baked 5 1/4 dozen peanut butter cookies and 4 5/6 dozen oatmeal cookies for a bake sale what was the number of dozen cooki
Doss [256]

Answer:

10\frac{1}{12} dozen

Step-by-step explanation:

\frac{1}{4} × 3 = \frac{3}{12}

\frac{5}{6} × 2 = \frac{10}{12}

\frac{3}{12}  + \frac{10}{12}  = \frac{13}{12}

\frac{13}{12} is equal to 1\frac{1}{12}

5 + 4 = 9 + 1\frac{1}{12} = 10\frac{1}{12} dozen


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3 years ago
What is 1/10 plus 8/100
pshichka [43]
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5 0
3 years ago
Which equation is represented by the graph below? <br> y=ex<br> y=ex-1<br> y=In x<br> y=in x-1
Vinil7 [7]

Answer: ex-1

Step-by-step explanation:

The -1 is used to show the parabola

4 0
4 years ago
Choose the best estimate for the multiplication problem below.
son4ous [18]

Hey there!

We see that the first factor is 82.17, which is about 80. Then, we have 7.32, which is about 7.

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5 0
3 years ago
What is a simple way to solve for the sum and difference of 2 cubes? For example, 27+64<img src="https://tex.z-dn.net/?f=x%5E3"
salantis [7]

Answer:

(3 + 4x)(9 - 12x + 16x²) = 0

(4m - 1)(16m² + 4m + 1) = 0

Step-by-step explanation:

Here we have to solve the sum of two cubes which is 27 + 64x^{3}

Now, the equation is 27 + 64x^{3} = 0

⇒ 3³ + (4x)³ = 0

⇒ (3 + 4x)[3² - 3(4x) + (4x)²] = 0

⇒ (3 + 4x)(9 - 12x + 16x²) = 0

So, (3 + 4x) = 0 or (9 - 12x + 16x²) = 0

Therefore, from the above two relation we can solve for x.

One root will be - \frac{3}{4} and the others we will get by applying Sridhar Acharya Formula, which will give a pair of conjugate imaginary roots of the equation.  

Again, we have to solve the difference of two cubes which is 64m^{3} - 1

Now, the equation is 64m^{3} - 1 = 0

⇒ (4m)³ - 1³ = 0

⇒ (4m - 1)[(4m)² + 4m(1) + 1²] = 0

⇒ (4m - 1)(16m² + 4m + 1) = 0

So, (4m - 1) = 0 or (16m² + 4m + 1) = 0

Therefore, from the above two relation we can solve for m.

One root will be \frac{1}{4} and the others we will get by applying Sridhar Acharya Formula, which will give a pair of conjugate imaginary roots of the equation.  (Answer)

8 0
4 years ago
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