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Firlakuza [10]
3 years ago
15

Keira has 3 1/8 pizzas. She splits it equally between her 5 friends. What fraction of the original pizzas does each friend get?

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
7 0

Answer:

52083/100000 all you need to do is divide it by 6

You might be interested in
3 (a) A random sample of 200 voters in a town is selected, and 114 are found to support an annexation suit. Find the 96% confide
hammer [34]

Answer:

a. 0.498 < p < 0.642

b. We are 96% sure that the error of estimator ^p = 0.57 will not exceed 0.07001

Step-by-step explanation:

Given;

Sample, n = 200 voters

Let x represent those that support annexation suit.

x = 114

First, we'll calculate the probability of supporting annexation suit.

Let p represent the probability of supporting annexation suit.

p = x/n

p = 114/200

p = 0.57

From elementary probability;

p + q = 1 where q represent probability of failure.

In this case, q represent probability of not supporting annexation suit

Substitute 0.57 for p

0.57 + q = 1

q = 1 - 0.57

q = 0.43

To find the 96% confidence interval for the fraction of the voting population favoring the suit;

The confidence interval is bounded by the following;

^p - z(α/2) √(pq/n) < p < ^p + z(α/2) √(pq/n)

At this point, we have values for p,q and n.

Next is to solve z(α/2)

First, we'll find the value of α/2 using

C.I = 100%(1 - α) where C.I = 96%

96% = 100%(1 - α)

1 - α = 96%

1 - α = 0.96

α = 1 - 0.96

α = 0.04

So,

α/2 = 0.04/2

α/2 = 0.02

So, z(α/2) = z(0.02)

Using normal probability table

z0.02 = 2.055 --- This is the closest value which leaves an area of 0.02 to the right and 0.98 to the left

Recalling our formula to solve 96% interval;

^p - z(α/2) √(pq/n) < p < ^p + z(α/2) √(pq/n)

By substituton, we have

0.57 - 2.055 * √(0.57*0.43/200) < p < 0.57 + 2.055 * √(0.57*0.43/200)

0.57 - 0.071939677073920 < p < 0.57 + 0.071939677073920

0.498060322926079 < p < 0.641939677073920 ---- Approximate

0.498 < p < 0.642

b. Here, we'll make use of the following theorem;

Using ^p as an estimate

We are 100%(1 - α) confident that the error will not exceed z(α/2) √(pq/n)

From (a), we have.

z(α/2) = 2.055, p = 0.57, q = 0.43, n = 200

By substituton, z(α/2) √(pq/n) becomes

2.055 * √(0.57 * 0.43/200)

= 2.055 * 0.071939677073920

= 0.070014284256857 ---- Approximate

= 0.07001

We are 96% sure that the error of estimator ^p = 0.57 will not exceed 0.07001

7 0
2 years ago
How do i solve 0.97 on a decimal number line?
e-lub [12.9K]
It's E because it is closer to 1 than the others and look at all the little lines and think of those as the tenths place
Please Mark Brainliest!!!!
5 0
3 years ago
A Food Marketing Institute found that 39% of households spend more than $125 a week on groceries. Assume the population proporti
Anuta_ua [19.1K]

Answer:

0.6210

Step-by-step explanation:

Given that a Food Marketing Institute found that 39% of households spend more than $125 a week on groceries

Sample size n =87

Sample proportion will follow a normal distribution with p =0.39

and standard error = \sqrt{\frac{0.39(1-0.39)}{87} } \\=0.0523

the probability that the sample proportion of households spending more than $125 a week is between 0.29 and 0.41

=P(0.29

There is 0.6210 probability that the sample proportion of households spending more than $125 a week is between 0.29 and 0.41

7 0
3 years ago
Eileen collected 78 empty cans to recycle, and Carl collected 62 cans. They packed an equal number of cans into each of seven bo
AVprozaik [17]

Answer:

20 cans

Step-by-step explanation:

Eileen collected 78 empty cans to recycle

Carl collected 62 empty cans to recycle

They pack equal number of cans in 7 boxes

Therefore the number of cans in each boxes can be calculated as follows.

= 62 + 78/7

= 140/7

= 20

Hence there were 20 cans in each boxes

8 0
2 years ago
What is the domain of this function?
Luda [366]
A

Explanation-
Domain is the X, which is also independent. So you look at the first circle, or in more detail, the circle that has arrows pointing AWAY from it.
4 0
2 years ago
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