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Dmitry_Shevchenko [17]
4 years ago
13

Divide 9.48 ÷ 0.24 = ______.

Mathematics
1 answer:
Ray Of Light [21]4 years ago
6 0

Answer:

39.5

Step-by-step explanation:

In the attached file

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Help me, I don't understand how to do it.
Levart [38]

Answer:

Aplha=105

Step-by-step explanation:

The perpendicular looks like double the base hence that angle is 30 and the other triangle have equal perpendicular and base, that angle is 45. So alpha+30+45=180, alpha=105

7 0
3 years ago
Hace 9 años mi tia tenia 30 años de edad ¿que edad tenia después de 9 años de edad?
4vir4ik [10]
Tu tia tenia 21 años de wear despues de 9 años de edad.
5 0
3 years ago
Which values of a, b, and c correctly represent the answer in simplest form? 3 and one-half divided by 2 and one-fourth = a Star
maria [59]

Answer:

a = 1, b = 5, c = 9

Step-by-step explanation:

3 1/2 ÷ 2 1/4

= 7/2 ÷ 9/4

= 7/2 × 4/9

= (7*4)/(2*9)

= 28/18

= 14/9

= 1 5/9

Therefore

3 1/2 ÷ 2 1/4 = a b/c

Where,

a = 1, b = 5, c = 9

7 0
3 years ago
Read 2 more answers
What is the average of the sixth even number, fifth and eighth odd number after 200?
ohaa [14]

<em>Answer:</em>

<em>212 is the answer !</em>

<em>Step-by-step explanation:</em>

<em>Firstly, We'll have to write all the numbers till 220 after 200 that is :</em>

<em>201  , 202  , 203 ,  204 , 205 , 206  , 207 , 208 , 209 , 210 , 211  ,212 , 213 , 214 , 215 , 216 , 217 , 218 , 219 , 220 . </em>

<em />

<em>Here we now know the the 6th even number is</em><em> 212.</em>

<em>And the 5th odd number is </em><em>209.</em>

<em>And the 8th odd number is</em><em> 215.</em>

<em />

<em>By using the formula we can find the average that is :</em>

<em>212+209+215/3  </em><em>= 636/3  = 212 </em>

<em />

<em>∴ Your answer is 212 !</em>

3 0
4 years ago
Read 2 more answers
Find the fourth roots of i
antoniya [11.8K]

Answer:

  1∠22.5°, 1∠112.5°, 1∠202.5°, 1∠292.5°

Step-by-step explanation:

A root of a complex number can be found using Euler's identity.

<h3>Application</h3>

For some z = a·e^(ix), the n-th root is ...

  z = (a^(1/n))·e^(i(x/n))

Here, we have z = i, so a = 1 and z = π/2 +2kπ.

Using r∠θ notation, this is ...

  i = 1∠(90° +k·360°)

and

  i^(1/4) = (1^(1/4))∠((90° +k·360°)/4)

  i^(1/4) = 1∠(22.5° +k·90°)

For k = 0 to 3, we have ...

 for k = 0, first root = 1∠22.5°

  for k = 1, second root = 1∠112.5°

  for k = 2, third root = 1∠202.5°

  for k = 3, fourth root = 1∠292.5°

4 0
1 year ago
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