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EleoNora [17]
3 years ago
7

Does this graph represent a function? Why or why not?

Mathematics
2 answers:
bija089 [108]3 years ago
8 0
D. No x value has more than one y value so it's a function.
Alexeev081 [22]3 years ago
5 0
<span>D.Yes, because it passes the vertical line test.</span>
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Can you help me please !
Bezzdna [24]

Answer:

Square root of 7 minus 2 equals x.

Step-by-step explanation:

X is irrational soooo

4 0
4 years ago
Job a, $15/hour, job b, $12/hour, how many hours at each job to earn $360
stira [4]

Answer:

Job A, will take 24 hours and Job B, will take 30 hours

Step-by-step explanation:

12 X 30 = 360 and 15 X 24 = 360

7 0
3 years ago
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Felix and Megan are going hiking and are trying to figure out how much water
andreev551 [17]

Answer:

w

Step-by-step explanation:

The amount of water they need to bring depends on how long they will be hiking.

4 0
1 year ago
A stadiums parking lot can accommodate 5,000 vehicles. If 35% of the 75,000 fans drive to tonight’s game with two fans per car h
geniusboy [140]

Answer:

35 percent of the 75,000 fans is: 0.35*75,000 = 26,250

since there are 2 fans per car we find the number of cars by dividing 26,250 by 2:

26,250 : 2 = 13,125 cars

5,000 will park at the stadium's parking lots, while the rest 13,125 - 5,000 = 8,125 cars will par at satellite lots.

OR

35% of 75000 = 26250

2 fans in a car

So, = 26250/2

= 13125

Total handling space = 5000

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Step-by-step explanation:

5 0
3 years ago
Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt
Paladinen [302]

Answer:

y(x)=4a\sqrt{3}* sin(x)-3a

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}

But:

\frac{1}{tan(x)} =cot(x)

So:

\frac{dy(x)}{dx} =cot(x)*(3a+y)

Multiplying both sides by dx and dividing both sides by 3a+y:

\frac{dy}{3a+y} =cot(x)dx

Integrating both sides:

\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx

Evaluating the integrals:

log(3a+y)=log(sin(x))+C_1

Where C1 is an arbitrary constant.

Solving for y:

y(x)=-3a+e^{C_1} sin(x)

e^{C_1} =constant

So:

y(x)=C_1*sin(x)-3a

Finally, let's evaluate the initial condition in order to find C1:

y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a

Solving for C1:

C_1=4a\sqrt{3}

Therefore:

y(x)=4a\sqrt{3}* sin(x)-3a

3 0
4 years ago
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