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vodka [1.7K]
3 years ago
7

An engineer believes that there is a linear relationship between the thickness of an air filter and the amount of particulate ma

tter that gets through the filter; that is, less pollution should get through thicker filters. The engineer tests many filters of different thickness and fits a linear model. If a linear model is appropriate, what should be apparent in the residual plot

Mathematics
1 answer:
kramer3 years ago
4 0

Answer:

If the model is appropiate, the residual of a linear regression model, when plotted in a scatter plot (residuals vs. independent variable), should be spread around 0, with no significant slope (slope = 0).

Step-by-step explanation:

The residual is defined as the difference between the observed and the predicted value.

If the model is appropiate, the residual of a linear regression model, when plotted in a scatter plot (residuals vs. independent variable), should be spread around 0, with no significant slope (slope = 0).

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A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)

Now

\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

               =\frac{24\times (-13)}{\sqrt{676}}

               =\frac{24\times (-13)}{26}

               = -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0
3 years ago
X+2>7 write the solution set in interval notation
REY [17]

Answer:

(5, infinitysymbol)

Step-by-step explanation:

First solve the inequality. Subtract 2 from both sides.

x + 2 > 7

x > 5

So that is one way of writing the answer and it is hopefully kind of understandable. X>5 means all the numbers greater (bigger) than 5, forever to infinity.

Interval notation is a way of writing a set or group of numbers. Interval notation uses ( ) parenthesis or [ ] square brackets. Then two numbers go inside with a comma in between. The first number is where the set of numbers start and the second number is where the set ends. You always put parenthesis around the infinity symbol or negative infinity symbol. You only use a square bracket if the inequality symbols have the "or equal to" underline under the > or <.

So x > 5 in interval notation is:

(5, infinitysymbol)

This shows that 5 is not included in the solution; and all the numbers forever bigger than five are solutions as well.

5 0
2 years ago
How do I solve this?
Ivenika [448]

\overline{XS}\cong\overline{YT}\Rightarrow 3m+7=4.2m+5\ \ \ |-7\\\\3m=4.2m-2\ \ \ \ |-4.2m\\\\-1.2m=-2\ \ \ \ |:(-1.2)\\\\m=\dfrac{2}{1.2}\\\\m=\dfrac{20}{12}\\\\m=\dfrac{5}{3}\to m=1\dfrac{2}{3}


\overline{YS}\cong\overline{XT}\Rightarrow3\dfrac{1}{2}r+2=2r+5\ \ \ \ |-2\\\\3\dfrac{1}{2}r=2r+3\ \ \ \ |-2r\\\\1\dfrac{1}{2}r=3\ \ \ |\cdot2\\\\3r=6\ \ \ \ |:3\\\\r=2

7 0
3 years ago
Describe the nature of the roots for the equation<br> 49x2– 28x +4 = 0
Zepler [3.9K]

Answer:

The roots of the equation is real and repeated

Step-by-step explanation:

Here, we want to describe the nature of the roots of the given quadratic equation

To get the nature of the roots, we find the discriminant of the equation

The discriminant is;

b^2 - 4ac

In this case, b = -28 , a = 49 and c = 4

The discriminant is thus;

-28^2 - 4(49)(4)

= 784 - 784 = 0

Since the discriminant is zero, this means that the quadratic equation has real roots which are the same

6 0
3 years ago
what equation in slope-intercept form represents the line that passes through the points (0,–7) and (–8,3)
Tema [17]

Answer:

y=-.5x-7

Step-by-step explanation:

6 0
3 years ago
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