The kinetic energy of a moving object is equal to the
work necessary to bring it to its speed from rest
If an object is moving, then it is able of doing work. It
has energy of motion, or also known as kinetic energy (KE). The kinetic energy
of a thing hinge on the heaviness of the object along with its speed.
To use standard enthalpies of formation to calculate the standard change in enthalpy for the melting of ice. kJ/mol
∆Hf° = standard heat of formation can be use to claculate the std enthalpy change as follows;
∆Hf°reaction = ∆Hf° p - ∆Hf° r
if the reaction is H₂O (s) ---- H₂O(l)
But
∆Hf°reaction = ∆Hf° H₂O(l) - ∆Hf° H₂O (s), which were -285kJ/mol and -291.8kJ/mol (obtained from the back of chemical process analysis text)
∆Hf°reaction = -285.8 kJ/mole - (-291.8 kJ/mole) = 6.0 kJ/mole = 6000 J/mole
heat gained by ice melting = heat lost by cooling water
(mass x ∆Hf°) ice = (mass x Cp x dT) liquid water
mass ice = (mass x Cp x dT) liquid water / (∆Hf°) ice
mass ice = 480 mL x 1.00 g/mL x 4.18 J/gC x (25-0 C) / 6000 J/mole
= 5.66 mole ice = 5.66 mole x 18.0 g /mole = 150 g of ice required to cool the 480mL of water.
Answer:
The temperature in degrees Fahrenheit in terms of the Celsius temperature is given by .
As we know by the linear relation
now we have
so we have
The temperature in degrees Celsius in terms of the Kelvin temperature is given by
As we know by the linear relation
now we have
the temperature in degrees Fahrenheit in terms of the Kelvin temperature .
As we know by the linear relation
now we have
so we have
Answer:The energy in fossil fuels (coal, oil, gas)
Explanation:
Answer:
v = 23.6 m/s
d = 78.48 m
Explanation:
Given that,
The initial speed of a car is 20 m/s
Acceleration of the car is 1 m/s²
Time, t = 3.6 s
We need to find the speed and the displacement of the car during this time.
Let v is the speed of the car. So,
Let d is the displacement of the car. It can be calculated as follows :
Hence, the speed and the displacement of the car during this time is 23.6 m/s and 78.48 m respectively.