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Klio2033 [76]
3 years ago
7

If the intensity of sound at a point is 4.33 x 10^-7 W/m^2, what is the sound level there? (Unit = dB)

Physics
1 answer:
DiKsa [7]3 years ago
7 0

Answer:

56.4 dB

Explanation:

Threshold of hearing, Ir = 1 * 10^-12

Intensity of sound, I = 4.33 * 10^-7

The sound level, L is calculated thus :

L = 10log(I / Ir)

L = 10log(4.33 * 10^-7 / 10^-12)

L = 10log(4.33 * 10^(-7+12))

L = 10log(4.33 * 10^5)

L = 10 * 5.6364878

L = 56.364878

L = 56.4 dB

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