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aev [14]
3 years ago
13

How many solutions does this linear system have?

Mathematics
1 answer:
Talja [164]3 years ago
4 0
The answer would be A: -2.5, 0
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Do Now (12/21/2020): Evelyn sees a TV on sale for $500. She has a coupon for 15% off the TV. What will be the final cost of the
likoan [24]

Answer:

$425

Step-by-step explanation:

500 × 0.15 = 75

500 - 75 = 425

3 0
3 years ago
Here is their argument. given the obtuse angle x, we make a quadrilateral abcd with ∠dab = x, and ∠abc = 90◦, and ad = bc. say t
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The error in the argument is in assuming that the line from p to d passes through line ab - that is, that pd crosses below a. But actually pd passes above a. This means that the angle pad is not equal to x + pab, but rather angle pad = 360-(x+pab). The rest of the "proof" then falls apart.

Step-by-step explanation:

7 0
4 years ago
If an object is launched at an angle of 28° with an initial velocity of 133 ft./s from a height of 6 feet how many seconds will
Tema [17]

Answer:

Hence after  3.98 sec  i.e  4 sec Object will hit the ground  .

Step-by-step explanation:

Given:

Height= 6 feet

Angle =28 degrees.

V=133 ft/sec

To Find:

Time in seconds after which it will hit the ground?

Solution:

<em>This problem is related to projectile motion for objec</em>t

First calculate the Range for object  and it is given by ,

R=v^2Sin(2Ф)/g

Here R= range  g= acceleration due to gravity =9.8 m/sec^2

1m =3.2 feet

So 9.8 m, equals to 9.8 *3.2=31.36 ft

So g=31.36 ft/sec^2. and 2Ф=2(28)=56

R=133^2*Sin(56)/31.36

R=14664.84/31.36

R=467.62  fts

Now using Formula for time and range as

R=VxT

Vx is horizontal velocity

Vx=V*cosФ

Vx=133*cos(28)

Vx=117.43  ft/sec

So above equation becomes as ,

467.62=117.43*T

T=467.62/117.43

T=3.98 sec

T is approximately equals to 4 sec.

4 0
4 years ago
PLS HELP! WULL MARK BRAINLIST!
zhuklara [117]
P2 is 4 Hope this helps :)
5 0
4 years ago
I need help I’m being timed
inna [77]

Answer:

acute Is the answer pretty sure

3 0
3 years ago
Read 2 more answers
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