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viktelen [127]
4 years ago
15

Help meh plz and god bless

Mathematics
1 answer:
Drupady [299]4 years ago
3 0

Answer:

25/9

Step-by-step explanation:

2/9+23/9=25/9

I am sure about this

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Select the correct solution set.
Kipish [7]

Step-by-step explanation:

50 \geqslant 15x \\  \\  \implies \:  \frac{50}{15}  \geqslant x\\  \\  \implies \:  \frac{10}{3}  \geqslant x \\  \\  \therefore \: x \leqslant \frac{10}{3}   \\ thus \:  \{x \: | \: x \leqslant \frac{10}{3}   \} \: is \: the \: correct \:  \\ solution \: set.

5 0
3 years ago
Alaya will paint the outside of a box with three different colors. Decide how she could paint the box. What is the total area th
laila [671]

Answer:

Decide how she could paint the box. Paint 2 sides of the box the same color.

What is the total area that each color will cover? The total area would be 2 sides of the box sides per color.

Step-by-step explanation:

The box has 6 sides. If Alaya will pain the box with 3 different colors...

6÷3=2

4 0
3 years ago
Which equation can be used to represent the statement?
Anvisha [2.4K]
Let the number is m

then:
<span>one-sixth of a number = 1/6 m = m/6

and:
</span><span>sum of one-sixth of a number and negative two = m/6 - 2

and:
</span>sum of one-sixth of a number and negative two is equal to negative two-thirds : m/6 - 2 = -2/3


solving for m:
m/6 - 2 = -2/3
m/6 = -2/3 + 2

m/6 = 4/3                  *6
m = 8

Your number is: six



Done

I hope that helps!



6 0
4 years ago
Read 2 more answers
BRAINLIESTT ASAP! PLEASE HELP ME :)<br> thanks!
fredd [130]

Answer:

A is correct, x=7, AB=20

Step-by-step explanation:

All of the options say x=7 so you can just input 7 into 4x-8 to find AB

4(7)-8=AB

28-8=AB

20=AB

Hope this helps, please mark brainliest :)

3 0
3 years ago
The angle \theta_1θ
enyata [817]

Answer:

sin\theta_1 = \dfrac{\sqrt{217}}{19}

Step-by-step explanation:

It is given that:

cos\theta_1 = -\dfrac{12}{19}

And we have to find the value of sin\theta_1 = ?

As per trigonometric identities, the relation between sin\theta\ and \ cos\theta can represented as:

sin^2\theta + cos^2\theta = 1

Putting \theta_1 in place of \theta Because we are given

sin^2\theta_1 + cos^2\theta_1 = 1

Putting value of cosine:

cos\theta_1 = -\dfrac{12}{19}

sin^2\theta_1 + (\dfrac{12}{19})^2 = 1\\\Rightarrow sin^2\theta_1 + \dfrac{144}{361} = 1\\\Rightarrow sin^2\theta_1 = 1-\dfrac{144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{217}{361}\\\Rightarrow sin\theta_1 = +\sqrt{\dfrac{217}{361}}, -\sqrt{\dfrac{217}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{\sqrt{217}}{19}, -\dfrac{\sqrt{217}}{19}

It is given that \theta_1 is in 2nd quadrant and value of sine is always positive in 2nd quadrant. So, the answer is.

\Rightarrow sin\theta_1 = \dfrac{\sqrt{217}}{19}

8 0
3 years ago
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