Answer:
(x)=-
-
Step-by-step explanation:
The answer you chose is correct. You should make sure that you check both of your intercepts before coming to a conclusion and determining your answer.
Hoped I helped!
Answer: The distance of Observer A from the radio antenna is what fraction of the distance of Observer B from the radio antenna?
It is 1/4.
Step-by-step explanation:
We know that the intensity of electromagnetic waves decreases with the radius squared, this means that we can write a simple relation as:
Intensity(r) = A/r^2
Observer A measures 16 the intensity of observer B.
if Ia is the intensity that observer A measures and Ib is the intensity that observer B measures, we have that:
Ia = 16Ib
A/(ra)^2 = 16*A/(rb)^2
1/(ra)^2 = 16/(rb)^2
rb^2 = 16*ra^2
and we know that 16 = 4*4 = 4^2
rb^2 = (4*ra)^2
then rb = 4*ra
this means that the distance between observer B and the antenna is equal to 4 times the distance between observer A and the antenna.
The fraction is ra = rb/4
The distance of
Observer A from the radio antenna is what fraction of the distance of Observer B from the radio antenna?
It is 1/4.
We are given expression:
.
Square root in exponent form is power
.
Therefore,
.
Now, replacing square root of 16 by
in original expression we are given, we get
.
Therefore,
<h3>

= 16 in simplest form. By the Power of Power rule,

. So,

must equal

in radical form.</h3>
Answer:
13 units
Step-by-step explanation:
-1 + (-8) = -9
|-9| = 9 + 4 = 13
(-9) is 13 units from 4
Hopefully this helps you :)
pls mark brainlest ;)