A coin dealer is having paper wraps made to go around a stack of coins. The coins have a diameter of 12 mm, and the dealer state s that the paper should be exactly 36 mm wide, or 3 times the diameter, to go around the coins. Is the coin dealer correct?
2 answers:
<span>No, the coin dealer is not correct. The paper would need to be at least 3.14 times the diameter to go around the coin. The circumference of the coin will be diameter times pi, so 12(3.14).</span>
No, not enough paper.
Should be 3.14 instead of 3.
The circumference will be 12 times pi.
(12)(3.14) = 37.68
You might be interested in
Answer:
3.3 recurring
Step-by-step explanation:
1) expand bracket
11-3a+6=27
2)rearrange equation
11+6=27+3a
11+6-27=3a
17-27=3a
-10=3a
-10/3=a
a=3.3 recurring
Answer:
Not sure of what your asking....
Step-by-step explanation:
equivalent to: 2(4x+5y)
15x - 5(3x-7) = 14
Answer:
it's 50 g
Step-by-step explanation:
it's like a multiplying assberry kehe
We have 2xπxr = 14π;
