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3 years ago

What do you multiply to get 8 and add to get 4

Mathematics

1 answer:

nasty-shy [4]3 years ago

3 0

Hi Mitchell

-1*8+12

(-1*8)+12

-8+12=4

I hope that's help :0

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Write the algebraic expression. twice the sum of x and 4

Cloud [144]

Answer: Y= X+4•2

Word form: Y equals X plus 4 times 2

5 0

3 years ago

In the expansion of (1/ax +2ax^2)^5 the coefficient of x is five. Find the value of the constant a.

DedPeter [7]

Answer:

80x⁴

Step-by-step explanation:

$(\frac{1}{ax} + 2ax^2)^5 = 5C_0(\frac{1}{ax})^5(2ax^2)^0 + 5C_1(\frac{1}{ax})^4(2ax^2)^1 + 5C_2(\frac{1}{ax})^3 (2ax^2)^2$

$+ 5C_3 (\frac{1}{ax})^2(2ax^2)^3 + 5C_4(\frac{1}{ax})^1(2ax^2)^4 + 5C_5(\frac{1}{ax})^0(2ax^2)^5$

$5C_0(\frac{1}{ax})^5(2ax^2)^0 =1 \times (\frac{1}{ax})^5 \times 1 = \frac{1}{a^5x^5}\\\\5C_1(\frac{1}{ax})^4(2ax^2)^1 = 5 \times (\frac{1}{ax})^4 \times (2ax^2)^1 = 10 ax^2 \times \frac{1}{a^4x^4} = \frac{10}{a^3x^2}\\\\5C_2 (\frac{1}{ax})^3 (2ax^2)^2= 10 \times (\frac{1}{ax})^3 \times (2ax^2)^2 = 10 \times \frac{1}{a^3x^3} \times 4a^2x^4 = \frac{40x}{a}\\\\5C_3 (\frac{1}{ax})^2 (2ax^2)^3 = 10 \times (\frac{1}{ax})^2 \times (2ax^2)^3 = 10 \times \frac{1}{a^2x^2} \times 8a^3 x^6 = 80ax^4\\\\$

$5C_4(\frac{1}{ax})^1(2ax^2)^4 = 5 \times \frac{1}{ax} \times 16a^4x^8 = 80a^3x^7\\\\5C_5(\frac{1}{ax})^0(2ax^2)^5 = 1 \times 1 \times 32a^5x^{10}$

The fourth term of the expansion has the constant a,

the coefficient of a is 80x⁴

6 0

3 years ago

When a power is raised to a power, what operation is performed on the exponents?

Alekssandra [29.7K]

Answer: The operation preformed is multiplication.

Step-by-step explanation: When you have a integer that is raised to a power, you must evaluate that integer first. For example, if you are asked to solve 2^3 + 4^7, you must first multiply. 2^3= 8 and 4^7= 16,384 then we must add these two products together to get 16,392.

How to find the product of to the power number: 8^3. We take eight and times it by it's self 3 times to get 512.

Hope this helps!

8 0

3 years ago

Convert polar equation to rectangular coordinates θ = − (9π/ 2)

yan [13]

Visualize pi/2 as 90° on the unit circle. this has no real component, only imaginary. same for 3pi/2, or -pi/2 as shown in this equation:

$- \frac{ \pi}{2} = 0 - i$

as you move around the unit circle, you'll find that 9pi/2 is the same angle as pi/2.

Thus, the rectangular coordinates are:
$- \frac{9\pi}{2} = 0 - i$

7 0

3 years ago

The diagram below represents the first three terms of a sequence. Assuming the pattern continues,which formula determines an, th

pishuonlain [190]

The correct answer is B) $a_n=3n+1$

Writing the sequence numerically, we have 4, 7, 10, ...

This is an arithmetic sequence, since there is a constant, 3, added each time. This gives us the explicit formula
$a_n=4+3(n-1)$

Using the distributive property, we have
$a_n=4+3*n-3*1
\\
\\a_n=4+3n-3$

Combining like terms, we have
$a_n=3n+1$

8 0

4 years ago

Read 2 more answers