Y² + 8y - 33 :
Break the expression into groups for formula ax²+ bx+c :
= (y²- 3y) + (11y - 33 )
Factor y from y² - 3y => y (y - 3)
Factor out 11 from 11 y - 33 => 11 (y - 3)
= y ( y- 3 ) + 11 ( y - 3 )
Factor out common term (y - 3 ) :
= ( y - 3 ) ( y + 11 )
hope this helps!
Answer:
15(
+b) or
15(b+
)
Step-by-step explanation:
First we can subtract the 4.
458 + 15b
Now we need to find the GCF, but they do not share any kinds of factors together. This might look ugly, but it is what it is. We factor out 15 to get b by itself.
15(
+b) or
15(b+
)
Answer:Part A: 13
Step-by-step explanation: look at the graph
That’s confusing do you know the formula your supposed to use?