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3 years ago

What division sentence means the same as the following subtraction sentences? 12-4=8, 8-4=4,4-4=0

Mathematics

1 answer:

raketka [301]3 years ago

5 0

Answer:

$\frac{12}{4}$

Step-by-step explanation:

write the division sentence that is same as the following subtraction sentences

$12-4=8$

$8-4=4$

$4-4=0$

From the given sentences , 4 is subtracted three times that starts from 12

division is a repeated subtraction

4 is subtracted till we get 0

so the division sentence for the following subtraction sentences is

$\frac{12}{4}$

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2 years ago

In a random sample of 45 newborn babies, what is the probability that 40% or fewer of the sample are boys. (Use 3 decimal places

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Answer:

$z= \frac{p- \mu_p}{\sigma_p}$

And the z score for 0.4 is

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And then the probability desired would be:

$P(p$

Step-by-step explanation:

The normal approximation for this case is satisfied since the value for p is near to 0.5 and the sample size is large enough, and we have:

$np = 45*0.4= 18 >10$

$n(1-p) = 45*0.6= 27 >10$

For this case we can assume that the population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Where:

$\mu_{p}= \hat p = 0.4$

$\sigma_p = \sqrt{\frac{p(1-p)}(n} =\sqrt{\frac{0.4(1-0.4)}(45}= 0.0703$

And we want to find this probability:

$P(p$

And we can use the z score formula given by:

$z= \frac{p- \mu_p}{\sigma_p}$

And the z score for 0.4 is

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And then the probability desired would be:

$P(p$

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3 years ago

Read 2 more answers

There are 10 marbles in a bag. Four are blue, 3 are black and 2 white and 1 red. If the marbles are not replaced once they are d

stich3 [128]

Given:

Given that there are 10 marbles in a bag. 4 are blue, 3 are black, 2 are white and 1 is red.

The marbles are selected by not replacing the drawn ones.

We need to the probability of selected a black marble and then a white marble without replacement.

Probability:

Let B denote the black marble.

Let W denote the white marble.

The probability of selecting a black marble is $P(B)=\frac{3}{10}$

The probability of selecting a white marble without replacement is $P(W)=\frac{2}{9}$

The probability of selecting a black marble and then a white marble without replacement is given by

$P(B \ and \ W)=P(B) \cdot P(W)$

Substituting the values, we get;

$P(B \ and \ W)=\frac{3}{10} \cdot \frac{2}{9}$

$P(B \ and \ W)=\frac{6}{90}$

$P(B \ and \ W)=\frac{1}{15}$

Thus, the probability of selecting a black marble and then a white marble without replacement is $\frac{1}{15}$

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