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2 years ago

Find the probability of no more than 2 successes in a trial of 5 in which the probability of success in any one trial is 18%

Mathematics

1 answer:

SSSSS [86.1K]2 years ago

4 0

Answer:

0.956

Step-by-step explanation:

X is the random variable representing the number of successes in the experiment in question;

X is represented by a binomial distribution with 5 trials and 0.18 probability of success, X~B (5, 0.18);

The probability of r successes, P(X=r), is found using the formula shown in second pic;

Working is shown in the other pic.

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Find a degree 3 polynomial with real coefficients having zeros 2 and 2 − 2 i and a lead coefficient of 1. Write P in expanded fo

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The polynomial with real coefficients having zeros 2 and 2 - 2i is

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Step-by-step explanation:

Given that a polynomial has zeros at 2 and 2 - 2i, we want to write this polynomial.

We have

x - 2 = 0

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x - (2 + 2i) = 0

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Now,

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2 years ago

Logb sqrt 29/61 <br><br> Is it logb (29-61)?? am i right

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Answer:

$log_b{\sqrt{\frac{29}{61}}=log_b(\sqrt{29}-\sqrt{61}})$

Step-by-step explanation:

We have been given the expression:

$log_b{\sqrt{\frac{29}{61}}$

We will use the property:

$log_a{\frac{n}{m}}=log_a{m-n}[$

Here, $a=b,n=\sqrt{29}\text{and}m=\sqrt{61}$

So, we will get from the identity:

$log_b{\sqrt{\frac{29}{61}}=log_b(\sqrt{29}-\sqrt{61})$

Hence, you are not right because you removed square rrot in final result rest is right.

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