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vladimir1956 [14]
3 years ago
8

Jillian walked 0.5 miles before she started jogging at an average pace of 5 miles per hour. The equation d = 0.5 + 5t can be use

d to relate the total distance, d, in miles to the time, t, that Jillian spent jogging. What are the independent and dependent variables? The independent variable is distance and the dependent variable is time. The independent variable is time and the dependent variable is distance. The independent variable is distance and the dependent variable is speed. The independent variable is speed and the dependent variable is distance.
Mathematics
2 answers:
viktelen [127]3 years ago
3 0
For this case we have the following equation:
 d = 0.5 + 5t
 We will describe the equation step by step.
 0.5: Initial distance Jillian walked
 5: speed with which Jillian begins to jog
 t: independent variable that indicates the number of hours
 y: dependent variable that indicates the distance traveled in miles
 Answer:
 
The variable variable is time and the dependent variable is distance.
Diano4ka-milaya [45]3 years ago
3 0

Answer B The independent variable is time and the dependent variable is distance.

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SOMEONE HELP PLEASE! ASAP!
Luba_88 [7]
When two lines intersect, the angles across from the intersection (the "X") are congruent (equal), and referred to as "vertical angles."
So by the rule of vertical angles are congruent, we can set them equal:
{x}^{2}  - 6x = 1\div2 \: x + 42 \\  {x}^{2}  - 6x - 1 \div 2 \: x = 42 \\  {x}^{2}  - 6.5x = 42
{x}^{2}  - 6.5x - 42 = 0 \\ multiply \: both\: sides \: by \: 2 \: to \: get \\ rid \: of \: the \: decimal \\ 2({x}^{2}  - 6.5x - 42) = 2(0)
2 {x}^{2}  - 13x - 84 = 0
to factor we need the factors of 84:
1×84, 2×42, 3×28, 4×21, 6×14
Now we need one of those factors ×2 ( from the x^2 term) minus the other factor to equal 13 (the middle term)
it turns out that if we use 4×21: 4×2 = 8
and 21-8 = 13. Woohoo! we got it
So now we have:
2 {x}^{2}  - 13x - 84 = 0 \\ (2x - 21)(x + 4) = 0
Now set each factor = 0
1) 2x - 21 = 0 and 2) x + 4 = 0
1) 2x - 21 = 0, 2x = 21, x = 21/2 = 10.5
2) x + 4 = 0, x = -4

Now we plug in each answer to check:
1) x = 10.5
{x}^{2}  - 6x =  {(10.5)}^{2}  - 6(10.5) \\  = 110.25 - 63 = 47.25
1/2x + 42 = 1/2(10.5) + 42 = 5.25 + 42 = 47.25
47.25 = 47.25
BAM SO IT LOOKS LIKE THAT'S IT!!
But let's check 2) first:
2) x = -4
{( - 4)}^{2}  - 6( - 4) = 16 + 24 = 40
1/2x + 42 = 1/2(-4) + 42 = -2 + 42 = 40
40 = 40, so both work!!
But it asks for m<1, and <1 is supplementary because it lies on same line, meaning the sum of both = 189
Therefore m<1 = 180 - 47.25 = 132.75°
OR m<1 = 180 - 40 = 140°


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