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Dahasolnce [82]

3 years ago

8

Solve the inequality y − 6>10

1 answer:

fredd [130]3 years ago

8 0

if y-6 > 10, and 16-6 = 10, then y > 16 since 17-6 = 11, which is greater than 10. Any number greater than 16 can fulfil this inequality.

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Factor.<br><br> <img src="https://tex.z-dn.net/?f=%2036t%5E%7B2%7D%20" id="TexFormula1" title=" 36t^{2} " alt=" 36t^{2} " align=

HACTEHA [7]

36t² - 1 =
(6t)² - 1² =
(6t-1)(6t+1)

6 0

3 years ago

Read 2 more answers

Help please now i cant figure it out

12345 [234]

Answer:

a. $\frac{-11}{24}$

b. $\frac{-3}{2} \\$

c. $\frac{31}{7}$

d. $\frac{11}{16}$

11, 3, 31, 11 = code

Step-by-step explanation:

a. $\frac{-1}{6}\\$ * 2 $\frac{3}{4}$ =

2 $\frac{3}{4}$ = $\frac{4*2+3 }{4}$ = $\frac{11}{4}$

$\frac{-1}{6}\\$ * $\frac{11}{4}$ = $\frac{-1*11}{6*4}$ = $\frac{-11}{24}$

b. $\frac{3}{16}$ / $\frac{-1}{8}$ =

$\frac{3}{16}$ * $\frac{8}{-1}$ = $\frac{3*8}{16*-1} \\$ = $\frac{24}{-16}$ = $\frac{-3}{2} \\$

c. $\frac{-31}{56}$ * $\frac{-8}{1}$ = $\frac{31}{7}$ (you can reduce 8 & 56 by dividing by 8: 56/8=7 & -8/8= -1)

d. 1 $\frac{7}{8}$ / 2 $\frac{8}{11}$ =

1 $\frac{7}{8}$ = $\frac{8*1+7}{8}$ = $\frac{15}{8}$

2 $\frac{8}{11}$ = $\frac{11*2+8}{11}$ = $\frac{30}{11}$

$\frac{15}{8}$ * $\frac{11}{30}$ = $\frac{11}{16}$ (you can reduce 15 & 30 by dividing by 15: 15/15=1 & 30/15 = 2)

4 0

3 years ago

What are the solutions to the equation 13x? - 17x + 7 = 0?<br> ©

ICE Princess25 [194]

Answer:

x=7/4

Step-by-step explanation:

13x-17x+7=0

-4x+7=0

-4x+7-7=0-7

-4x=-7

-4x/-4=-7/-4

x=7/4

8 0

3 years ago

12,548 rounded to the nearest thousand and 4,685 rounded to the nearest thousand

ehidna [41]

Answer:

12,548 rounded to the nearest thousand is 13,000 and 4,685 rounded to the nearest thousand is 5,000

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Which describes how to find the solution 5k >22

inysia [295]

Answer:

<h2>k > 4.4</h2>

Step-by-step explanation:

$5k>22\qquad\text{divide both sides by 5}\\\\\dfrac{5k}{5}>\dfrac{22}{5}\\\\k>4\dfrac{2}{5}\to k>4.4\to k\in(4.4,\ \infty)$

8 0

3 years ago