All categories

4 years ago

Renaming Fractions as Percents

Mathematics

1 answer:

krek1111 [17]4 years ago

8 0

WHat grade level are you that would help me to know mark me brainliest for answer

You might be interested in

A rhombus is a four-sided figure with all sides the same length. Points F(-2,-2), G(-2, 3), and H(2, 6) are three vertices of rh

masya89 [10]

Answer:

Step-by-step explanation:

The sides of the 4-sided figure are the same length, so we can find the perimeter (sum of side lengths) by multiplying one side length by 4.

<h3>Side length</h3>

Points F(-2, -2) and G(-2, 3) lie on the same vertical line: x = -2. The distance between them is the difference of their y-coordinates:

FG = (3 -(-2)) = 5

Each side is 5 units long.

<h3>Perimeter</h3>

The length of the four sides is ...

P = 4s = 4(5) = 20

The perimeter of the rhombus is 20 units.

5 0

2 years ago

PLEASE HELP!!! ASAP The function graphed approximates the height of a rock, in meters, x seconds after it falls from a cliff

nasty-shy [4]

The vertical numbers are the distance and the horizontal numbers are the time in seconds.

Look at where the line is located at the number 20.

It si between the 2 and the 3 on the horizontal line, but you can see it is closer to the 2 than it is the 3, so the time would be 2.2s

8 0

3 years ago

Read 2 more answers

If x = −4 is a zero of the polynomial function f(x) = 2x3 + 13x2 + 23x + 12, which of the following is another zero of f(x)? x

Talja [164]

Answer:

x= -1 is the another zero of the given function.

Step-by-step explanation:

We have been given a function:

$f(x)=2x^3+13x^2+23x+12$

The zero of the function is that point where the function vanishes or the value of the function becomes zero.

From the given four values we will put the values in the function and wherever we get zero is the zero of the function.

put x= -1 we get:

$f(-1)=2(-1)^3+13(-1)^2+23(-1)+12$

$f(-1)=-2+13-23+12=0$

Hence, x= -1 is the another zero of the given function.

5 0

3 years ago

Read 2 more answers

Need help with this maybe question

Aleonysh [2.5K]

Answer:

the vertex is:

(2, -1)

Step-by-step explanation:

First solve the equation for the variable y

$x^2-16y-4x-12=0$

Add 16y on both sides of the equation

$16y=x^2-16y+16y-4x-12$

$16y=x^2-4x-12$

Notice that now the equation has the general form of a parabola

$ax^2 +bx +c$

In this case

$a=1\\b=-4\\c=-12$

Add $(\frac{b}{2}) ^ 2$ and subtract $(\frac{b}{2}) ^ 2$ on the right side of the equation

$(\frac{b}{2}) ^ 2=(\frac{-4}{2}) ^ 2$

$(\frac{b}{2}) ^ 2=(-2) ^ 2$

$(\frac{b}{2}) ^ 2=4$

$16y=(x^2-4x+4)-4-12$

Factor the expression that is inside the parentheses

$16y=(x-2)^2-16$

Divide both sides of the equality between 16

$\frac{16}{16}y=\frac{1}{16}(x-2)^2-\frac{16}{16}$

$y=\frac{1}{16}(x-2)^2-1$

For an equation of the form

$y=a(x-h)^2 +k$

the vertex is: (h, k)

In this case

$h=2\\k =-1$

the vertex is:

(2, -1)

6 0

3 years ago

1.75x+1.25y=2<br> 7x+5y=9<br> how many solutions does this system of equations have?

Zepler [3.9K]

Answer:

Step-by-step explanation:

1.75x+1.25y=2 Multiply this equation by 4

7x + 5y = 8

7x+5y=9

As you can see, the xs and ys have the same coefficient. These lines are parallel. There are NO solutions. Just to show you that, here is a graph.

6 0

3 years ago