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timurjin [86]
3 years ago
13

MASTER ANSWERE? #TRIG​

Mathematics
1 answer:
vekshin13 years ago
6 0

tan(angle) = opposite leg / adjacent leg

tan(20) = x /10

x = 10 * tan(20)

x = 3.6

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Write the equation of the line shown in point-slope form. (2,1) (3,8)
Ulleksa [173]

<u>Answer:</u>

The line equation that passes through the given points is 7x – y = 13

<u>Explanation:</u>

Given:

Two points are A(2, 1) and B(3, 8).

To find:

The line equation that passes through the given two points.

Solution:

We know that, general equation of a line passing through two points (x1, y1), (x2, y2) in point slope form is given by

\frac{(y- y1)}{(x-x_1)}= \frac{((y_2- y_1)}{(x_2- x_1 )}

{(y- y1)= \frac{((y_2- y_1)}{(x_2- x_1 )}\times(x-x_1)..........(1)

here, in our problem x1 = 3, y1 = 8, x2 = 2 and y2 = 1.

Now substitute the values in (1)

(y-8) = \frac{(1 - 8)}{(2 - 3)}\times(x- 3)

(y -8) = \frac{(- 7)}{(-1)}(x-3)

y – 8 = 7(x – 3)

y – 8 = 7x – 21  

7x – y = 21 – 8  

7x – y = 13  

Hence, the line equation that passes through the given points is 7x – y = 13

3 0
3 years ago
The answer to this problem?
LenaWriter [7]

The simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

<h3>How to simplify the expression?</h3>

The expression is given as:

\sqrt{\frac{162x^9}{2x^{27}}}

Divide 162 and 2 by 2

\sqrt{\frac{81x^9}{x^{27}}}

Take the square root of 81

9\sqrt{\frac{x^9}{x^{27}}}

Apply the quotient rule of indices

9\sqrt{\frac{1}{x^{27-9}}}

Evaluate the difference

9\sqrt{\frac{1}{x^{18}}}

Take the square root of x^18

\frac{9}{x^9}

Hence, the simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

Read more about expressions at:

brainly.com/question/723406

#SPJ1

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Two other numbers are 15.48 and 15.52
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