Step-by-step explanation:
Find the Center and Radius (x-4)^2+y^2=4
(
x
−
4
)
2
+
y
2
=
4
This is the form of a circle. Use this form to determine the center and radius of the circle.
(
x
−
h
)
2
+
(
y
−
k
)
2
=
r
2
Match the values in this circle to those of the standard form. The variable
r
represents the radius of the circle,
h
represents the x-offset from the origin, and
k
represents the y-offset from origin.
r
=
2
h
=
4
k
=
0
The center of the circle is found at
(
h
,
k
)
.
Center:
(
4
By definition of cubic roots and power properties, we conclude that the domain of the cubic root function is the set of all real numbers.
<h3>What is the domain of the function?</h3>
The domain of the function is the set of all values of x such that the function exists.
In this problem we find a cubic root function, whose domain comprise the set of all real numbers based on the properties of power with negative bases, which shows that a power up to an odd exponent always brings out a negative result.
<h3>Remark</h3>
The statement is poorly formatted. Correct form is shown below:
<em>¿What is the domain of the function </em>![y = \sqrt[3]{x - 1}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B3%5D%7Bx%20-%201%7D)
<em>?</em>
<em />
To learn more on domain and range of functions: brainly.com/question/28135761
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Answer: the area of the triangle is 23.4 cm²
Step-by-step explanation:
The given triangle is not a right angle triangle. Since two sides and one angle are known, we can either apply the Heron's formula or the Sine formula which is expressed as
Area of triangle = 1/2abSinC
Where a and b are the sides of the triangle and C is the given angle. Therefore,
Area = 1/2 × 8.2 × 6.4 × Sin63
Area = 1/2 × 8.2 × 6.4 × 0.8910
Area = 23.4 cm² to the nearest tenth.
Answer:
f(2) = 16
or
y = 16
Step-by-step explanation:
Step 1: Write out function
y = 6x + 4
Step 2: Define variable for problem
<em>x</em> = 2
Step 3: Plug into function f(x)
f(2) = 6(2) + 4
f(2) = 12 + 4
f(2) = 16
Step 4: Change f(2) to y
y = 16
Answer:
vertex : (-5/2, -53/4)
solutions: (-(5-sqrt53)/2, 0) (-(5+sqrt53)/2, 0)
Step-by-step explanation:
