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Setler [38]
3 years ago
8

Consider a t distribution with 24 degrees of freedom. Compute P(-1.27˂t˂1.27) . Round your answer to at least three decimal plac

es.
Mathematics
1 answer:
DENIUS [597]3 years ago
3 0

Answer:

Step-by-step explanation:

  1. <em>Use the calculator provided to solve the following problems. </em>
  2. <em> </em>
  3. <em>Consider a t distribution with 24 degrees of freedom. Compute P(-1.27˂t˂1.27) . Round your answer to at least three decimal places. </em>
  4. <em> </em>
  5. <em>Consider a t distribution with 5 degrees of freedom. Find the value of c such that P(t≤c)=0.05 . Round your answer to at least three decimal places.</em>
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What is tje equation of the function?
crimeas [40]

Answer:

It is relatively easy to determine whether an equation is a function by solving for y. When you are given an equation and a specific value for x, there should only be one corresponding y-value for that x-value. For example, y = x + 1 is a function because y will always be one greater than x.

Step-by-step explanation:

8 0
3 years ago
Consider two vectors A and B A=14i and B= -4i+8j
DaniilM [7]
Assuming \mathbf a,\mathbf b\in\mathbb R^3, you have

\mathbf a\cdot\mathbf b=(14)(-4)+(0)(8)=-56

so

((\mathbf a\cdot\mathbf b)\,\mathbf i)\cdot\mathbf a=(-56\,\mathbf i)\cdot(14\,\mathbf i)=(-56)(14)=-784

Next,

\mathbf a+\mathbf b=(14\,\mathbf i)+(-4\,\mathbf i+8\,\mathbf j)=10\,\mathbf i+8\,\mathbf j

Then

(\mathbf a+\mathbf b)\times\mathbf b=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\10&8&0\\-4&8&0\end{vmatrix}=112\,\mathbf k

((\mathbf a+\mathbf b)\times\mathbf b)\times\mathbf k=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\0&0&112\\0&0&1\end{vmatrix}=\mathbf 0
4 0
3 years ago
Someone solve this please.
laila [671]
The answer is one hundred
7 0
3 years ago
Help me plz help me plz
Lisa [10]

Answer:

A: 1 crackers = 95/4 cals

B: mass= 16/4

c: 15/4

4 0
2 years ago
Read 2 more answers
A bottling company uses a filling machine to fill plastic bottles with cola. The bottles are supposed to contain 300 milliliters
PilotLPTM [1.2K]

Answer:

e. 0.0072

Step-by-step explanation:

We are given that a bottling company uses a filling machine to fill plastic bottles with cola. And the contents vary according to a Normal distribution with Mean, μ = 298 ml and Standard deviation, σ = 3 ml .

 Let    Z = \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)  where, Xbar = mean contents of six randomly

                                                                     selected bottles

                                                          n = sample size i.e. 6    

So, Probability that the mean contents of six randomly selected bottles is less than 295 ml is given by, P(Xbar < 295)

 P(Xbar < 295) = P( \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } } < \frac{295 - 298}{\frac{3}{\sqrt{6} } } ) = P(Z < -2.45) = P(Z > 2.45)

Now, using z% score table we find that P(Z > 2.45) = 0.00715 ≈ 0.0072 .

Therefore, option e is correct .

7 0
3 years ago
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