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pav-90 [236]
3 years ago
6

Jimmy successfully factors a quadratic $4x^2 + bx + c$ as \[4x^2 + bx + c = (Ax + B)(Cx + D),\]where $A,$ $B,$ $C,$ and $D$ are

integers. What are all the possible values of $A$?
Mathematics
1 answer:
saul85 [17]3 years ago
3 0

Answer:

±1, ±2, and ±4

Step-by-step explanation:

4x² + bx + c = (Ax + B) (Cx + D)

Distribute:

4x² + bx + c = ACx² + (AD + BC) x + BD

Matching the coefficients, AC = 4.  So A must be a factor of 4.  Possible values of A are therefore ±1, ±2, and ±4.

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1/2 is a fraction so it is 5
8 0
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If the area of a triangle is 124.8 what is the base and height
Elena L [17]

I think it would be 14.2  and 8.8

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Divide and answer in simplest form: 1 2 ÷ 4 A) 1 8 B) 2 1 C) 4 2 D) 8 1
denis23 [38]
\dfrac{1}{2}  \div 4 =  \dfrac{1}{2}  \times \dfrac{1}{4}  = \dfrac{1}{8}


Answer: 1/8 (Answer A)
4 0
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Jerome spent $20 on supplies to make 50 cookies for a bake sale. Write and solve an inequality to find the price that Jerome sho
Semenov [28]

Answer:

Each cookie will have to be sold for at least $0.90 if the profit is to be made is more than $25.

Step-by-step explanation:

The amount spent on supplies is $20.

The number of cookies baked is = 50.

If the profit to be made is more than $25.00 .

Then we can safely say that all the cookies have to be sold for

= $20.00 + $25.00

= $45.00

Therefor the required inequality can be written as

50 x ≥ $45.00            ⇒       x   ≥   \frac{45.00}{50}            ⇒      x   ≥  $0.90.

Therefore we can say that each cookie will have to be sold for at least $0.90 if the profit is to be made is more than $25.

7 0
3 years ago
If you cut away a triangle of area 59 cm² from a square, the remaining area will be 85 cm². Find the length of the side of the s
siniylev [52]
So the square was fine, then the triangle decided to go for a hike.

now, if the triangle when it took off, it took 59 cm², and the square was left all by its lonesome with only 85 cm², that means with the triangle in it, the square is then 59 + 85 cm², or 144 cm².

\bf \textit{area of a square}\\\\
A=s^2\qquad 
\begin{cases}
s=\textit{length of a side}\\
---------\\
A=144
\end{cases}\implies 144=s^2
\\\\\\
\sqrt{144}=s
\implies 12=s
3 0
3 years ago
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