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pav-90 [236]
3 years ago
6

Jimmy successfully factors a quadratic $4x^2 + bx + c$ as \[4x^2 + bx + c = (Ax + B)(Cx + D),\]where $A,$ $B,$ $C,$ and $D$ are

integers. What are all the possible values of $A$?
Mathematics
1 answer:
saul85 [17]3 years ago
3 0

Answer:

±1, ±2, and ±4

Step-by-step explanation:

4x² + bx + c = (Ax + B) (Cx + D)

Distribute:

4x² + bx + c = ACx² + (AD + BC) x + BD

Matching the coefficients, AC = 4.  So A must be a factor of 4.  Possible values of A are therefore ±1, ±2, and ±4.

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The answer is approximately 0.14 
5 0
3 years ago
A bag contains 25 balls 20 of which are blue what percentage of balls are not blue
Artist 52 [7]

Answer:

20%

Step-by-step explanation:

20/25 = blue

This means 5/25 of the balls in the bag are NOT blue

(25-20 = 5)

We need to convert 5/25 to a percentage

\dfrac{5}{25} = \dfrac{5\times4}{25\times4}=\dfrac{20}{100}

% = per cent

"per" means "out of"

"cent" means "one hundred"

so

20/100 = 20%

7 0
1 year ago
How many unique triangles can be drawn with side lengths 8 in., 12 in., and 24 in.? Explain
Debora [2.8K]

By using the triangular inequality, we will see that no triangles can be made with these side lengths.

<h3>How many triangles can be made with these side lengths?</h3>

Remember that for any triangle with side lengths A, B, and C, the triangular inequality must be true.

This means that the sum of any two sides must be larger than the other side.

A + B > C

A + C > B

B + C > A.

For the given side lengths, we will have:

8 in + 12 in > 24 in

8in + 24 in > 12 in

12 in + 24 in > 8 in.

Now, notice that the first inequality is false. So the triangular inequality is not meet. Then we can't make a triangle with these side lengths.

So we can make 0 unique triangles with these side lengths.

If you want to learn more about triangles:

brainly.com/question/2217700

#SPJ1

5 0
2 years ago
What is the product of the fractions represented by these two area models?
Hoochie [10]

Answer:You'll have to show us what 2 area models

Step-by-step explanation:

5 0
3 years ago
In a city, 60% of the residents live in houses and 40% of the residents live in apartments. Of the people who live in houses, 20
Step2247 [10]
75%; so if we say there are 100 people in this city that means 60 of them live in houses and 40 of them live in apartments. Of the 60 living in houses 20% of them (12% of total population; 60 x .20) own their own business and those in apartments (40) 10% of them (4% of total pop.; 40 x .10) have their own business. In total 16 of the 100 people have businesses and 12 of those people live in houses so 12/16 equals .75. We multiply this by 100 to get the percent so there’s 75% that a person who owns a business in this city will also live in a house.
6 0
3 years ago
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