A=adult pay
c=child pay
3a+4c=83
2a+3c=59
subtract
a+c=24
2a+2c=48
2a+3c-2a-2c=59-48
c=11
a=24-11=13
price of adult ticket=13$
price of child's ticket=$11
a. At its maximum height, the ball has zero vertical velocity, so
b. The ball's height in the air 
at time 
is given according to
Solve for when 
:
The first answer in the choices
Answer:
-36 • (22u + 1)
Step-by-step explanation:
Pulling out like terms :
2.1 Pull out like factors :
-74u - 5 = -1 • (74u + 5)
Equation at the end of step 2 :
(6 • (58u + 1)) - -6 • (74u + 5)
Step 3 :
Equation at the end of step 3 :
6 • (58u + 1) - -6 • (74u + 5)
Step 4 :
Pulling out like terms :
4.1 Pull out 6
Note that -6 =(-1)• 6
After pulling out, we are left with :
6 • ( (-1) * (58u+1) +( (-1) * (74u+5) ))
Step 5 :
Pulling out like terms :
5.1 Pull out like factors :
-132u - 6 = -6 • (22u + 1)
Final result :
-36 • (22u + 1)
Using product and quotient property:
log x + log y can be displayed as log xy
Because we're subtracting 2 log z we can use the power property to rewrite this as log z^2
Now, using quotient property we can display this expression as:
<h3>log xy/z^2</h3>
