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BARSIC [14]
3 years ago
13

Questions below. Please show work. 40pt and brainiest. Thanks!

Mathematics
1 answer:
Sever21 [200]3 years ago
4 0

Answer:

Step-by-step explanation:

The transformation of f(x) to g(x) = a·f(x-b)+c does vertical scaling by a factor of "a", right shift by the amount "b" and shift upward by the amount "c".

__

1. The function is ...

  • scaled vertically by a factor of 3,
  • shifted right 2 units, and
  • shifted up 5 units.

The general shape is that of the square root function, but enlarged vertically and translated upward and to the right. The first attachment shows a graph.

__

2. The function is ...

  • scaled vertically by a factor of -1 (reflected across the x-axis), and
  • shifted down 8 units.

The function is an odd function, so is symmetrical about the origin. A reflection across the x-axis (top/bottom) has the same appearance as a reflection across the y-axis (left/right). This function retains its size, but is moved downward. The second attachment shows a graph.

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If f(x)=4x+12x and g(x)=5x-1 find (f+g)(x)
Anastasy [175]
You just have to combine like terms 4x+5x +12 -
1 = 9x+11 I am not sure if it is 12x or just 12 if it is 12x the answer is 21x-1
4 0
4 years ago
(2a^x +1/2 b^x)^2 thank you!!!!!!!!!!!!!!!!!!!1
kogti [31]
Note that (a+b)^2 = a^2 + 2ab + b^2.

Therefore, 
                                                                              b^x         (b^x )^2
<span>(2a^x +1/2 b^x)^2 becomes (2a^x)^2 + 2(2a^x)(-------- ) + ------------
                                                                                 2               4

LCD is 4.  Thus, we have
                                             
            4 [ (2a^(2x) ] + 8</span>a^x*b^x + b^(2x)
<span>                                  </span>
3 0
4 years ago
Find the common difference of the sequence shown 1/6,1/3,1/2,2/3,......
tekilochka [14]

Answer:

Common Difference(d) is    

               d=\frac{1}{6}

Step-by-step explanation:

Given sequence is :

                 \frac{1}{6}, \frac{1}{3} ,\frac{1}{2} ,\frac{2}{3} .........

If a sequence has a constant common difference throughout the sequence, then the sequence is called Arithmetic Progression.

Considering a sequence:

       a_1,a_2,a_3,a_4..........\\

a_2-a_1=a_3-a_2=a_4-a_3=a_n-a_n_-_1=d

where 'd' is the common difference of the A.P.

Similarly, finding the common difference of the given sequence.

       

                           \frac{1}{3} -\frac{1}{6}= \frac{1}{2}- \frac{1}{3}=\frac{2}{3} - \frac{1}{2}=d\\

                              d=\frac{1}{3}-\frac{1}{6}=\frac{(2)(1)-(1)(1)}{6}=\frac{1}{6}

                                   d=\frac{1}{6}

Common Difference(d) is    

               d=\frac{1}{6}

8 0
3 years ago
Read 2 more answers
Solve linear equations :
AlladinOne [14]

Answer: 7.) Wrong Question

8.) 8

(9.) - 2

Step-by-step explanation:

7.) 10n - 11 = 3 + 4n + 6n

Collect like terms

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It's not possible to have zero n = 14

8.) -8(k + 4) = - 96

Exland the bracket

-8k - 32 = - 96

Collect like terms

-8k = - 96 + 32

-8k = - 64

Divide through by -8

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k = 8

9.) -6(2k + 5) + 7k = -6 + 7k

Open the bracket

-12k - 30 +7k = -6 + 7k

Collect like terms

-12k + 7k - 7k = - 6 + 30

-12k = 24

Divide both sides by -12

-12k/-12 = 24/-12

k = -2

5 0
3 years ago
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