You just have to combine like terms 4x+5x +12 -
1 = 9x+11 I am not sure if it is 12x or just 12 if it is 12x the answer is 21x-1
Note that (a+b)^2 = a^2 + 2ab + b^2.
Therefore,
b^x (b^x )^2
<span>(2a^x +1/2 b^x)^2 becomes (2a^x)^2 + 2(2a^x)(-------- ) + ------------
2 4
LCD is 4. Thus, we have
4 [ (2a^(2x) ] + 8</span>a^x*b^x + b^(2x)
<span> </span>
Answer:
Common Difference(d) is

Step-by-step explanation:
Given sequence is :

If a sequence has a constant common difference throughout the sequence, then the sequence is called Arithmetic Progression.
Considering a sequence:


where 'd' is the common difference of the A.P.
Similarly, finding the common difference of the given sequence.



Common Difference(d) is

Answer: 7.) Wrong Question
8.) 8
(9.) - 2
Step-by-step explanation:
7.) 10n - 11 = 3 + 4n + 6n
Collect like terms
10n - 4n - 6n = 3 + 11
10n - 10n = 14
It's not possible to have zero n = 14
8.) -8(k + 4) = - 96
Exland the bracket
-8k - 32 = - 96
Collect like terms
-8k = - 96 + 32
-8k = - 64
Divide through by -8
-8k/-8 = - 64/-8
k = 8
9.) -6(2k + 5) + 7k = -6 + 7k
Open the bracket
-12k - 30 +7k = -6 + 7k
Collect like terms
-12k + 7k - 7k = - 6 + 30
-12k = 24
Divide both sides by -12
-12k/-12 = 24/-12
k = -2
U want this simplified???