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slamgirl [31]
3 years ago
8

Their sum is −7 and their difference is 14 what are my numbers

Mathematics
1 answer:
Mashcka [7]3 years ago
8 0

Answer:

Answer: 3 1/2 and -10 1/2 are the two numbers.

Step-by-step explanation:

Let x and y be the two unknown numbers.

x+y=-7 [Given]

x-y=14 [Given]

x-y=14 [Given]

x=y+14 [Add y to both sides]

x+y=-7 [Given]

(y+14)+y=-7 [Subtitution]

2y+14=-7 [Combine like terms]

2y=-21 [Subtract 14 from both sides]

y=-21/2 [Divide both sides by 2]

y=-10 1/2 [Division]

x-y=14 [Given]

x=y+14 [Add y to both sides]

x=-10 1/2 + 14 [Substitution]

x= 3 1/2 [Addition]

Check:

x+y=-7 [Given]

3 1/2 + -10 1/2?=-7 [Substition]

-7=-7 [Addition]

QED

x-y=14 [Given]

3 1/2 - -10 1/2?=14 [Substitution]

3 1/2 + 10 1/2?=14 [Change the sign of the subtrahend and add]

14=14 [Addition]

QED

Answer: 3 1/2 and -10 1/2 are the two numbers.

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Answer:

1. 2(x+2)(x+5)

2. 8(x+4)^{2}

Step-by-step explanation:

<u>Problem #1:</u>

1. Find the GCF (Greatest Common Factor)

GCF = 2

2. Factor out the GCF and simplify.

2(x^{2} +7x+10)

3. Factor x^{2} +7x+10

<u>Which two numbers add up to 7 and multiply to 10?</u>

2 and 5

<u>Rewrite the expression using the above.</u>

(x+2)(x+5)

4. Done!

2(x+2)(x+5)

<u>Problem #2:</u>

1. Find the GCF (Greatest Common Factor)

GCF=8

2. Factor out the GCF and simplify.

8(x^{2} +8x+16)

3. Use the perfect square formula. a^{2} +2ab+b^{2} =(a+b)^{2}

a = x\\b=4

(x+4)^{2}

4. Done!

8(x+4)^{2}

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