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3 years ago

What kind of problems could be solved with GCF and LCM

Mathematics

2 answers:

Effectus [21]3 years ago

6 0

Answer:

GCF: when you need to find the greatest amount of groups

LCM: when you need to find the shortest amount of something

Step-by-step explanation:

Thepotemich [5.8K]3 years ago

4 0

Answer:

word problems

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Vanessa exercised by walking around a pond. One day, she walked 3 3/8 mi. The distance around the pond is 3/8 mi.

REY [17]

Let n be the number of times she walked around the pond

(3 3/8) / (3/8) = n

=> 9 = n

Vanessa walked around the pond 9 times

7 0

3 years ago

Read 2 more answers

10. Multi-Step Mrs. Sullivan calculates that she

snow_tiger [21]

Answer:

Amount of paint to be bought = 10 gallons

Step-by-step explanation:

Amount of paint needed by Mrs. Sullivan to paint her house = 12 gallons

She is already having paint = 8 quarts

Since, 1 quart = 0.25 gallons

Therefore, 8 quarts = 8 × 0.25

= 2 gallons

So, amount of paint she is already having = 2 gallons

Amount of paint to be bought = 12 - 2

= 10 gallons

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2 years ago

Which of the following is the value of a when the function f(x) = 3xl is written in the standard form of an absolute value

Feliz [49]

Answer:

D. 3

Step-by-step explanation:

For g(x) = |x|, we seem to have ...

f(x) = 3|x| = 3g(x) = a·g(x)

The value of 'a' is 3.

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2 years ago

Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to

RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

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2 years ago

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Answer:

Ok thats really cool thanks :)

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3 years ago