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Elena-2011 [213]
3 years ago
15

The table below shows the cost of bananas at a local grocery store.

Mathematics
2 answers:
yuradex [85]3 years ago
4 0

Answer:

yes 5 is right

Step-by-step explanation:

timama [110]3 years ago
3 0

Answer:

5

Step-by-step explanation:

0.75x5=3.75

Hoped this helped

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Round your answers to one decimal place, if necessary.
MA_775_DIABLO [31]

Answer:

Mean=12.5

Median=13

Step-by-step explanation:

What you do for the mean is you add all the numbers together to get 75.

You will then divide it by 6 because there are 6 numbers to get 12.5 as your answer.

The median all you do is find the middle number. The middle numbers are 12 and 14. You will take 12 and 14 and add them together to get 26.

You will then divide it by 2 to get 13 as your answer.

8 0
3 years ago
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Show that h= r(csc(theta)-1)
Alex

Answer:

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2 years ago
Mike runs for the president of the student government and is interested to know whether the proportion of the student body in fa
Alik [6]

Answer:

We conclude that the proportion of student body in favor of him is significantly less than or equal to 50%.

Step-by-step explanation:

We are given that Mike runs for the president of the student government and is interested to know whether the proportion of the student body in favor of him is significantly more than 50 percent.

A random sample of 100 students was taken. Fifty-five of them favored Mike.

<em>Let p = </em><u><em>proportion of the students who are in favor of Mike.</em></u>

So, Null Hypothesis, H_0 : p \leq 50%      {means that the proportion of student body in favor of him is significantly less than or equal to 50%}

Alternate Hypothesis, H_A : p > 50%      {means that the proportion of student body in favor of him is significantly more than 50%}

The test statistics that would be used here <u>One-sample z proportion</u> <u>statistics</u>;

                        T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of students body in favor of Mike = \frac{55}{100} = 0.55

           n = sample of students taken = 100

So, <em><u>test statistics</u></em>  =   \frac{0.55-0.50}{\sqrt{\frac{0.55(1-0.55)}{100} } }

                               =  1.01

The value of z test statistics is 1.01.

<em>Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.</em>

<em>Since our test statistic is less than the critical value of z as 1.01 < 1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><u><em>we fail to reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that the proportion of student body in favor of him is significantly less than or equal to 50% or proportion of the students in favor of Mike is not significantly greater than 50 percent.

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3 years ago
A rectangle has an area of 112 m2. The length is 12 m more than four times the width. What is the length of a diagonal of the re
tankabanditka [31]
The answer is 1,344 hope this helps
3 0
3 years ago
32 is an example of
TEA [102]

Step-by-step explanation:

A. a numerical expression I am pretty sure

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