Answer:
if you want a t*-value for a 90% confidence interval when you have 9 degrees of freedom, go to the bottom of the table, find the column for 90%, and intersect it with the row for df = 9. This gives you a t*–value of 1.833 (rounded).
Step-by-step explanation:
Hope this helps!
The slope--- 5.2x represents how much income is increased based on the worker's experience year
the y-int ------ 22 represent if the worker has no experience then he gets $22 income
b) the way you can tell the cost of income in 19 years is to estimate it using your ruler or just eyeball it
I'm sure you don't need this becuz u post this question a week ago
The average rate of change of a graph between two intervals is given by the difference in value of the values on the graph of the two interval divided by the difference between the two intervals.
Part A.
From the graph the average Valentine's day spending in 2005 is 98 while the average Valentine's day spending in 2007 is 120.
The average rate of change in spending between 2005 and 2007 is given by

Part B
From the graph the average Valentine's day spending in 2004 is 100 while the average Valentine's day spending in 2010 is 103.
The average rate of change in spending between 2004 and 2010 is given by

Part C:
From the graph the average Valentine's day spending in 2009 is 102 while the average Valentine's day spending in 2010 is 103.
The average rate of change in spending between 2009 and 2010 is given by
7392/6 pluge into colculater you will get 1232