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3 years ago

Please explain this to me UwU

Mathematics

2 answers:

ki77a [65]3 years ago

7 0

Each answer possibility is a coordinate and represents a variety of an (x,y) point. The equation states that y = 32x + 27, so to find the correct answer, u must find the (x,y) coordinate that makes each side equal to the other. Plug in each number accordingly...

(y) = 32(x) + 27

a. (248) = 32(8) + 27

b. (379) = 32(11) + 27

c. (354) = 32(6) + 27

d. (288) = 32(9) + 27

now it’s just a matter of simplifying to see which equation is true.

a. 248 =/ 283

b. 379 = 379

c. 354 =/ 219

d. 288 =/ 315

The only equation that is true is B.

Mariana [72]3 years ago

7 0

Answer:

owo

Step-by-step explanation:

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liubo4ka [24]

Answer:

167 Pages Left To Read

Step-by-step explanation:

15*5=75

75*5=375

375+ 25*10=625

792-625=167

8 0

3 years ago

5/8 divided by 1 1/3 equals?

Hitman42 [59]

Step-by-step explanation:

5/8 x 3/11 = answer

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5 0

3 years ago

Read 2 more answers

Find the variable of each pair

Lera25 [3.4K]

A. X=4
B. Y= 24, X= 6

5 0

3 years ago

Can someone help me ASAP!!

Lana71 [14]

The answer is 5.

Step-by-step explanation:

To find the interquartile range you must look at the median and the upper and lower halves of the data. The median (12) to the upper half of the data (15) is 3. Next, look at the median (12) to the lower half of the data (10) it is 2. We then add 2 and 3 to get the interquartile range of 5.

6 0

3 years ago

From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s

Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

60 out of 100 scores are passing scores, hence $n = 100, \pi = \frac{60}{100} = 0.6$

95% confidence level

So $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7$

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

5 0

3 years ago