X^4+ 3x^3+4x^2-8 | x+2 = x^3+x^2+2x-4
-x^4-2x^3
-----------------------
x^3+4x^2-8
-x^3-2x^2
-------------------------
2x^2-8
-2x^2-4x
--------------
-4x-8
4x+8
----------------------------
/ /
is a factor because (x+2)(x^3+x^2+2x-4)=x^4+3x^3+4x^2-8
Answer:
No solution
Step-by-step explanation:
3x+12-4=2x+8+x
3x+8=2x+8+x
3x+8=3x+8
sub tract 3x on both sides and poof
we get 8 =8
High Hopes^^
Barry-
Answer:
yes
Step-by-step explanation:
My friend says 5 is 60 and 6 is b.
This is what is called a literal equation. Solve it for m just like you would solve any equation for x. Isolate the term with the variable you're looking for. Do this by subtracting 4cm from both sides to give you g - 4cm = -3m. Now we need to divide by -3 to get m alone:

. Or we could lose the negative on the 3 in the denominator like this:

and

. There you go! Any one of those last three would work. It just depends upon how your teacher wants you to express your answer.