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Veronika [31]
3 years ago
12

Samuel pulls two coin out of his pocket randomly without replacement. If his pocket contains one nickel, one dime, and one quart

er, what is the probability that he pulled more than 20 cents out of his pocket? Justify your work by creating a tree diagram or a sample space.
Mathematics
1 answer:
Ilya [14]3 years ago
4 0
2:3 3 possible options (quarter+dime= 35, quarter+nickel=30, dime+nickel=15) two options are more than 20
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What is the quotient when the sum of 13 and 11 is divided by the difference of 13 and 11
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Help with those three please!!
Scilla [17]

Answer:

Part 1) Option A. The axis of symmetry is x=4

Part 2) Option C. minimum

Part 3) Option A. (4,-4)

Part 4) Option B. (2,0) and (6,0)

Step-by-step explanation:

we have

f(x)=x^{2}-8x+12

Part 1) What is the axis of symmetry of the parabola described by the equation above?

we know that

The equation above is a vertical parabola open upward

The axis of symmetry is the x-coordinate of the vertex

Find the vertex of the parabola (convert the equation in vertex form)

f(x)-12=x^{2}-8x

f(x)-12+16=x^{2}-8x+16

f(x)+4=x^{2}-8x+16

f(x)+4=(x-4)^{2}

f(x)=(x-4)^{2}-4 ----> equation in vertex form

The vertex of the parabola is (4,-4)

so

The axis of symmetry is x=4

Part 2) The vertex of the equation above is also

we know that

The equation above is a vertical parabola open upward

therefore

The vertex is a minimum

Part 3) What is the vertex of the parabola described by the equation above

we know that

The equation of the parabola into vertex form is equal to

f(x)=(x-4)^{2}-4

therefore

The vertex of the parabola is (4,-4)

Part 4) What are the  x-intercepts of the parabola described by the equation above

we know that

The x-intercepts are the values of x when the value of y is equal to zero

so

f(x)+4=(x-4)^{2}

f)x)=0

so

4=(x-4)^{2}

take square root both sides

(x-4)=(+/-)2

x=4(+/-)2

x=4(+)2=6

x=4(-)2=2

therefore

The x-intercepts are

(2,0) and (6,0)

7 0
2 years ago
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