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4 years ago

9

A fair die is rolled 360 times. Find the probability that: a) less than50 results are a 6. B) between 55 and 65 results (inclusi

ve) are a 6

1 answer:

Karolina [17]4 years ago

8 0

For this problem, you haven = 360p = 1/6q = 5/6 E[x] = np = 360*1/6 = 60SD[x] = √(npq) = √(360*1/6*5/6) = √(50) ≈ 7.07

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$17.54

Step-by-step explanation:

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3 years ago

Read 2 more answers

Is the point 3/5 and 4/5 corresponds to an angle in the unit circle what is the csc

Mariulka [41]

<u>Answer:</u>

csc = 5/4

<u>Step-by-step explanation:</u>

Assuming that the two given points 3/5 and 4/5 are the two sides of a triangle and a right angle 0 with legs x and y and z as its hypotenuse.

Then using Pythagoras Theorem:

$z^2=x^2+y^2$

$z^2=(\frac{3}{5} )^2+(\frac{4}{5} )^2$

$z^2 = \frac{9}{25} + \frac{16}{25}$

$z^2=\frac{25}{25}$

$z^2=1$

Taking square root on both the sides:

$z=1$

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Therefore, csc = 5/4.

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4 years ago

Suppose 250 randomly selected people are surveyed to determine if they own a tablet. Of the 250 surveyed, 98 reported owning a t

SashulF [63]

Answer:

The true proportion for the population would be between 0.386 and 0,398 (0.392±0.06) in 95% confidence level.

Step-by-step explanation:

Confidence interval for true population proportion can be computed as p±ME where

p is the sample proportion ( $\frac{98}{250}=0.392$ )
ME is the margin of Error from the mean

and margin of error (ME) can be found using the formula

ME= $\frac{z*\sqrt{p*(1-p)}}{\sqrt{N} }$ where

z is the corresponding statistic in 95% confidence level (1.96)
p is the sample proportion ( $\frac{98}{250}=0.392$ )

N is the sample size (250)

Using the numbers

ME= $\frac{1.96*\sqrt{0.392*0.608}}{\sqrt{250} }$ ≈ 0.06

Then the true proportion for the population would be p±ME = 0.392±0.06 in 95% confidence level.

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Answer:

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