The given equation is:
y = -10x + 1
Slope of this equation = -10
New line will be perpendicular to this line, so slope of new line = 1/10
So, we are to find the equation of a line with slope 1/10 and passing through (5,7). Using the point slope form we can write
y - 7 = 1/10 ( x - 5)
y = x/10 -1/2 + 7
y = x/10 + 13/2
⇒
x/10 - y = -13/2
So option C gives the correct equation of the new line
Let the 1st number be x; 2nd number be y; 3rd number be z.
x + y + z = 79
x = number we are looking for.
y = x * 5 ==> 5 times the first
z = x + 16 ==> 16 more than the first
Therefor,
x + (x * 5) + (x+16) = 79
1st step, multiply the 2nd number: x * 5 = 5x
x + 5x + x + 16 = 79
Add all like numbers:
7x + 16 = 79
To get x, transfer 16 to the other side and change its sign from positive to negative.
7x = 79 - 16
7x = 63
To get x, divide both sides by 7
7x/7 = 63/7
x = 9
To check. Substitute x by 9.
x + (x * 5) + (x+16) = 79
9 + (9 * 5) + (9 + 16) = 79
9 + 45 + 25 = 79
79 = 79 equal. value of x is correct.
3y - 1 < 3
Isolate the y. Treat the less than or equal like an equal sign.
Do the opposite of PEMDAS. First, add 1 to both sides
3y - 1 (+1) < 3 (+1)
3y < 4
Next, divide 3 from both sides
3y/3 < 4/3
y < 4/3
y < 4/3 is your answer
hope this helps
