Let's make,
mechanic #1's rate = x
mechanic #2's rate = y
* Their rate is dollars per hour ($/hr)
mechanic #1 worked for 20 hours (hr × $/hr = $)
20x = money earned by mech#1
and mechanic #2 worked for 5 hours
5y = money earned by mech#2
together they charged a total of $1150. So the amount of money earned by both mechanics.
20x + 5y = 1150
the sum of the two rates was $95 per hour.
x + y = 95
which means
x = 95 - y
plug (95 - y) in for "x" in the other equation to get everything in terms of one variable.
20(95 - y) + 5y = 1150
solve for y
1900 - 20y + 5y = 1150
1900 - 15y = 1150
-15y = 1150 - 1900
-15y = -750
y = -750/-15
y = 50 $/hr
Now use this to solve for x
x + y = 95
x + 50 = 95
x = 95 - 50
x = 45 $/hr
mech#1 charged 45$/hr
mech #2 charged 50$/hr
You need to use a common denominator. The least common denominator of 11 and 22 is 22.
3/22 + -1/11 = 3/22 + -2/22 = 3/22 - 2/22 = 1/22
Answer:
Part A:
C= cash Sue earns
H = hours Sue works
C is dependent upon H because C only changes when H is changed.
Part B:
(0,0)
(1,6)
Part C:
C=6H
The questions is, when z=9, 3z = ? When you multiply 3*9, you get 27
