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2 years ago

Simply 20-3[4(z+1)-6(z-2)]

Mathematics

1 answer:

creativ13 [48]2 years ago

8 0

Answer:

The answer is 6z-28

Step-by-step explanation:

20 - 3[4(z+1) - 6(z-2)]

= 20 - 3(4z+4-6z+12)

= 20 - 3(16 - 2z)

= 20 - 48 + 6z

= 6z - 28

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3,000 ÷ 50=300 ÷ 5 =?

Dvinal [7]

I’m guessing it’s 60

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2 years ago

A student counted the number of times her teacher said word like during her class over an 11- day period [likes per class period

hichkok12 [17]

Let us calculate the median; the 6th observation is 20, so it is 20. We need the 6th observation so that out of the 11 observations we have 5 above the median and 5 below (or equal). We also have that then Q1 is the median of the lowest 5 observations, hence 19 (14,16,19,19,20, the 3rd observation is 19). Similarly, we get that the median for the upper half of the observations, Q3 namely, is 22 (21,21,22,22,23, the 3rd observation is 22). Thus, the interquartile range is 3=Q3-Q1. According to our calculations, all observations are wrong.

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2 years ago

Read 2 more answers

Please help me and explain thank you so much I appreciate it

andreev551 [17]

Answer:

He gets 32, $10 bills.

Step-by-step explanation:

He puts in $630.

3 times $50 equals $150.

8 times $20 equals $160.

$150 plus $160 equals $310.

$630 minus $310 equals $320.

$320 divided by 10 equals 32.

So he gets 32, $10 bills.

8 0

2 years ago

If a line goes through the point (8,9) and has a slope of negative 3/4 what is the starting value?

scZoUnD [109]

I assume by starting value, you mean y-intercept. The y-intercept is 15

To find this, we need to use slope intercept form and the given information to find it.

y = mx + b ----> plug in the known values

9 = -3/4(8) + b

9 = -6 + b

15 = b

Therefore, the starting value is 15.

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2 years ago

A lake polluted by bacteria is treated with an antibacterial chemical. Aftertdays, thenumber N of bacteria per milliliter of wat

jeyben [28]

Answer:

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Step-by-step explanation:

<u>Extrema values of functions </u>

If the first and second derivative of a function f exists, then f'(a)=0 will produce values for a called critical points. If a is a critical point and f''(a) is negative, then x=a is a local maximum, if f''(a) is positive, then x=a is a local minimum.

We are given a function (corrected)

$N(t) = 20(t^2-lnt^2)+ 30$